What part of the electromagnetic spectrum can cause sunburn? radio waves infrared light gamma rays ultraviolet light

A device that detects small current differences and prevents electrocution that is often required as a safety measure for bathro

choli [55]

A device that detects small current differences and prevents electrocution that is often required as a safety measure for bathroom, kitchen, and exterior outlets is referred to as: Ground-fault interrupter.

<h3>What are arc-fault circuit interrupter?</h3>

According to "Article 100 Arc-Fault Circuit interrupter (AFCI)," arc-fault circuit interrupter is an electrical device which is designed and developed to deenergize the electrical circuit whenever it detects and recognizes characteristics unique to arcing.

Similarly, a ground-fault interrupter simply refers to an electrical device that is designed and developed for the detection of small current differences in an electrical circuit.

The main purpose of a ground-fault interrupter is to prevent electrocution or electrical shock and as such, it is an important safety measure for the following areas in a building:

Bathroom
Kitchen
Exterior outlets

Read more on ground-fault interrupter here: brainly.com/question/12615861

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7 0

1 year ago

Is hot asphalt that is poured into the ground and cools a physical or chemical change?

Gala2k [10]

Physical change
Because it's changed by heat

5 0

4 years ago

Read 2 more answers

Mass is measured in ____________, and weight is measured in ______________.

chubhunter [2.5K]

Answer:

MASS is measured in KILOGRAMS

Weight is measured in NEWTONS

Explanation:

7 0

3 years ago

Read 2 more answers

Healthy pregnant women should get at least 150 minutes of moderate-intensity aerobic activity, spread over a 7-day period, each

kirill115 [55]

Healthy pregnant women should get at least 150 minutes of moderate-intensity aerobic activity, spread over a 7-day period, each week - True

<u>Explanation:</u>

Women who are healthy but moderately active must be engaged with aerobic activities moderately. they should be engaged with this activities at least 2 and a half hours in all 7 days of a week. They must be engaged with this activity during the pregnancy time and also in the period after their delivery.

During the time of pregnancy all women must be healthy and physically active. The ways for maintaining a very good health in the pregnancy time will be guided by the health care providers. Women should be highly active during and after pregnancy time. This helps in having a baby that is also very healthy.

3 0

3 years ago

A spaceship negotiates a circular turn of radius 2925 km at a speed of 29960 km/h. (a) What is the magnitude of the angular spee

emmainna [20.7K]

a) 0.0028 rad/s

b) $23.68 m/s^2$

c) $0 m/s^2$

Explanation:

a)

When an object is in circular motion, the angular speed of the object is the rate of change of its angular position. In formula, it is given by

$\omega = \frac{\theta}{t}$

where

$\theta$ is the angular displacement

t is the time interval

The angular speed of an object in circular motion can also be written as

$\omega = \frac{v}{r}$ (1)

where

v is the linear speed of the object

r is the radius of the orbit

For the spaceship in this problem we have:

$v=29,960 km/h$ is the linear speed, converted into m/s,

$v=8322 m/s$

$r=2925 km = 2.925\cdot 10^6 m$ is the radius of the orbit

Subsituting into eq(1), we find the angular speed of the spaceship:

$\omega=\frac{8322}{2.925\cdot 10^6}=0.0028 rad/s$

b)

When an object is in circular motion, its direction is constantly changing, therefore the object is accelerating; in particular, there is a component of the acceleration acting towards the centre of the orbit: this is called centripetal acceleration, or radial acceleration.

The magnitude of the radial acceleration is given by

$a_r=\omega^2 r$

where

$\omega$ is the angular speed

$r$ is the radius of the orbit

For the spaceship in the problem, we have

$\omega=0.0028 rad/s$ is the angular speed

$r=2925 km = 2.925\cdot 10^6 m$ is the radius of the orbit

Substittuing into the equation above, we find the radial acceleration:

$a_r=(0.0028)^2(2.925\cdot 10^6)=23.68 m/s^2$

c)

When an object is in circular motion, it can also have a component of the acceleration in the direction tangential to its motion: this component is called tangential acceleration.

The tangential acceleration is given by

$a_t=\frac{\Delta v}{\Delta t}$