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sergeinik [125]

3 years ago

13

An automobile is sitting on a hill which is 20 m higher than ground level. Find the mass of the automobile if it contains 362,60

0 J of potential energy

1 answer:

mr Goodwill [35]3 years ago

6 0

M= ?
g=9.8 m/s (2)
h=20 m

Eg=362,600 J
Eg/mg

362,600 J/9.8 m/s (2) x 20 m
=1,850 m

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VMariaS [17]

The gravitational force between Mars and the Sun is $1.65\cdot 10^{21} N$

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

$F=G\frac{m_1 m_2}{r^2}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this problem, we have:

$m_1 = 1.99\cdot 10^{30} kg$ is the mass of the Sun

$m_2 = 6.39\cdot 10^{23} kg$ is the mass of Mars

$r=229\cdot 10^6 km = 229\cdot 10^9 m$ is the average distance Mars-Sun

Substituting into the equation, we find the gravitational force:

$F=(6.67\cdot 10^{-11})\frac{(1.99\cdot 10^{30})(6.39\cdot 10^{23})}{(229\cdot 10^9)^2}=1.62\cdot 10^{21} N$

So, the closest answer is

$1.65\cdot 10^{21} N$

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4 0

4 years ago

A 0.144 kg baseball is moving towards home plate with a speed of 43.0 m/s when it is bunted. the bat exerts an average force of

Ganezh [65]

As per impulse momentum theorem we know that

$F\Delta t = m(v_f - v_i)$

now here we will have

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t = 1.30 ms

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$v_i = -43 m/s$

now we need to find final speed using above formula

$(6.50 \times 10^3)(1.30 \times 10^{-3}) = 0.144 ( v_f - (-43))$

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3 years ago

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professor190 [17]

Answer:

The International Space Station move at 7.22 km/s.

Explanation:

Orbital speed of satellite is given by $v=\sqrt{\frac{GM}{r}}$ , where G is gravitational constant, M is mass of Earth and r is the distance to satellite from centre of Earth.

r = R + h = 6350 + 1400 = 7750 km = 7.75 x 10⁶ m

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M = 5.98 x 10²⁴ kg

Substituting

$v=\sqrt{\frac{6.673\times 10^{-11}\times 5.98\times 10^{24}}{7.75\times 10^6}}=7223.86m/s=7.22km/s$

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3 years ago

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Andrew [12]

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3 years ago

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Natalija [7]

Answer:

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Explanation:

Given that the speed of train A, $V_A$ = 45 m/s from west to east.

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So, the speed of train A from east to west= - 45 m/s

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Hence, the speed of train B w.r.t train A is 105 m/s from east to west.

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3 years ago