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3 years ago

5

there are 15 rafts available for people to use on the adventure river ride. each raft holds 12 people. the park runs this ride 3

times each hour. how many people can ride the wild river in 1 hour if all of the rafts are used and each raft is full?

1 answer:

3241004551 [841]3 years ago

6 0

540 people can ride the wild river in 1 hour if all of the rafts are used and each raft is full

<u>Solution:</u>

Given, There are 15 rafts available for people to use on the adventure river ride.

Each raft holds 12 people.

Then, total people capacity over all rafts = 15 x 12 = 180 people.

The park runs this ride 3 times each hour.

We have to find how many people can ride the wild river in 1 hour if all of the rafts are used and each raft is full?

Then, <em>total people count who take ride = number of rides x number of people per ride </em>

= 3 x 180 = 540

Hence, 540 people can take ride in 1 hour.

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An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and

egoroff_w [7]

Answer:

a) $P(140$

$P(0.036$

$P(0.036$

b) $P(140< \bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(139,28.1)$

Where $\mu=139$ and $\sigma=28.1$

We are interested on this probability

$P(140$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(140$

And we can find this probability like this:

$P(0.036$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(0.036$

Part b

For this case we select a sample size of n =32. Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=139, \frac{\sigma}{\sqrt{n}}=\frac{28.1}{\sqrt{32}}=4.97)$

And the new z score would be:

$Z=\frac{\bar X -\mu}{\sigma_{\bar x}}$

$P(140< \bar X$

$P(140< \bar X$

5 0

3 years ago

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp

olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = $\overline{x}$ = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data speeds i.e. x - $\overline{x}$

x - $\overline{x}$ = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between carrier's highest data speed and the mean of all 50 data speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

$\frac{59.98}{20.03}=2.99$

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

$z=\frac{x-\overline{x}}{s}$

Using the given values, we get:

$z=\frac{75.6-15.62}{20.03}=2.99$

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the carrier's highest data speed is significantly higher.

3 0

3 years ago

Find the mean and range. 18 23 10 39 22 17 16 15

stepan [7]

Answer:

Hey there the answer to your question will be below

Step-by-step explanation:

Mean=20

Range=29

___________________________________________________

Range:

Xmas = 39 and Xmas = 10

39-10=29

____________________________________________________

Mean:

160/8 = 20

Hope that helps!

By: xBrainly

7 0

3 years ago

11x + 12 = 8x - 9 ... please

Marat540 [252]

Assignment: $\bold{\Solve \ Equation: \ 11x+12=8x-9}$

<><><><><><><>

Answer: $\boxed{\bold{x=-7}}$

<><><><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><><><>

[ Step One ] Subtract 12 From Both Sides

$\bold{11x+12-12=8x-9-12}$

[ Step Two ] Simplify

$\bold{11x=8x-21}$

[ Step Three ] Subtract 8x From Both Sides

$\bold{11x-8x=8x-21-8x}$

[ Step Four ] Simplify

$\bold{3x=-21}$

[ Step Five ] Divide Both Sides By 3

$\bold{\frac{3x}{3}=\frac{-21}{3}}$

[ Step Six ] Simplify

$\bold{x=-7}$

<><><><><><><>

$\bold{\rightarrow Mordancy \leftarrow}$

4 0

3 years ago

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sineoko [7]

Answer:

52

Step-by-step explanation:

angle RQS=180-90-34=90-34=56

and then

180-56=x+72

124=x+72

x=52

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2 years ago

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