Answer:
- equation = input("Enter an equation: ")
-
- if("+" in equation):
- operands = equation.split("+")
- result = int(operands [0]) + int(operands[1])
- print(operands[0] + "+" + operands[1] + "=" + str(result))
- elif("-" in equation):
- operands = equation.split("-")
- result= int(operands [0]) - int(operands[1])
- print(operands[0] + "-" + operands[1] + "=" + str(result))
- elif("*" in equation):
- operands = equation.split("*")
- result = int(operands [0]) * int(operands[1])
- print(operands[0] + "*" + operands[1] + "=" + str(result))
- elif("/" in equation):
- operands = equation.split("/")
- result = int(operands [0]) / int(operands[1])
- print(operands[0] + "/" + operands[1] + "=" + str(result))
- elif("%" in equation):
- operands = equation.split("%")
- result = int(operands [0]) % int(operands[1])
- print(operands[0] + "%" + operands[1] + "=" + str(result))
Explanation:
The solution code is written in Python 3.
Firstly prompt user to enter an equation using input function (Line 1).
Create if-else if statements to check if operator "+", "-", "*", "/" and "%" exist in the input equation. If "+" is found (Line 3), use split method to get the individual operands from the equation by using "+" as separator (Line 5). Output the equation as required by the question using string concatenation method (Line 6). The similar process is repeated for the rest of else if blocks (Line 7 - 22).
Answer:
there is no car on a bus a bus is one long vehicle
Explanation:
.docx is the default file extension on a Word doc.
To support a position
It’s the only answer that makes sense so you’ll have to figure out the rest but to support a position is definitely correct
<u>The answer is:</u> ROW
<u>Explanation:</u>
Each table have records in the form of row. That's why the collection of rows and columns is called table. And each records is a row in table.
I hope you get the idea.
Thanks
