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weeeeeb [17]
3 years ago
12

Match the vocabulary terms to their definitions.

Physics
2 answers:
Ostrovityanka [42]3 years ago
8 0

Answer: The answer above is correct! I got 100% :))

Explanation:

DedPeter [7]3 years ago
7 0

Answer:

Distance-           The length along a path between two points .

Velocity-            The rate and direction at which an object moves .

Displacement-  The net change in position of an object .

Vector-               A measurement that has both magnitude and direction .

Speed-               Measure of the rate at which an object changes position .

Momentum-      The mass of an object multiplied by its velocity.

Explanation:

Vector: A physical quantity having both magnitude and direction is called Vector quantity. Example: Displacement, Velocity, Acceleration, Force etc.

On the other hand , quantity having only magnitude is called Scalar. Example: Distance, Speed, Time, Current etc.

Distance: The totle length of path traversed by a body in certain time is called distance. It is scalar quantity as it has only magnitude. SI unit of distance is meter.

Displacement: It is defined as change in position of a body in given period of time. Actually it is the distance between initial and final position along with given direction. So it is vector quantity. SI unit is meter.

Speed: The rate at which distance is traveled with respect to time is called speed.It is scalar quantity. SI unit is meter/second.

                                    Speed=\frac{Distance}{Time}

Velocity: It can be defined as rate of change in position or displacement with respect to time.It is vector quantity. SI unit is meter/second.

                                    Velocity=\frac{Displacement}{Time}

Momentum: The amount of motion contain in a body is the momentum. It is defined as product of mass and velocity. It is vector quantity. SI unit is kg.meter/second

                                    Momentum=Mass×Velocity

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Explanation:

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v(t)=\frac{dx(t)}{dt}\\\\\Rightarrow dx(t)=v(t)dt

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v(t)=\frac{dx(t)}{dt}\\\\\int dx(t)=\int v(t)dt\\\\x(t)=\int \frac{5}{t^{\frac{1}{2}}}dt\\\\\therefore x(t)=\frac{5}{0.5}\int t^{-0.5}dt\\\\x(t)=10\sqrt{t}+c

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