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3 years ago

Which conclusion about the atom can be drawn from Rutherford’s gold foil experiment?

Physics

2 answers:

ivolga24 [154]3 years ago

7 0

The answer is: D
Explanation: I Learned it in class
Hope this helps :)

Drupady [299]3 years ago

6 0

D. Rutherford found that the atom consists of a small positively charged nucleus.

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The velocity of a particle (m = 10 mg, q = –4.0 μC) at t = 0 is 20 m/s in the positive x direction. If the particle moves in a u

kompoz [17]

Answer:

Vf = - 20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction).

Explanation:

Given:

Vi = 20 m/s, m= 10 mg =1 × 10⁻⁵ kg, q= -4.0 × 10⁻⁶ C , E= 20 N/C. t= 5.0 s

first to find Electric Force

F= Eq = 20 × -4.0 10⁻⁶ C = - 8 × 10⁻⁵ N (-ve sign shows that the field will push the particle opposite to positive x- direction)

We also have F=ma

⇒ a = F/m = - 8 × 10⁻⁵ N / 10 × 10⁻⁵ kg = -8 m/s² ( -ve sign shows that the particle is accelerated opposite to positive x- direction)

Now according the first equation of Motion.

Vf = Vi + at

Vf = 20 m/s + -8 m/s² × 5 s

Vf= -20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction)

6 0

4 years ago

Jake drops a book out of a window from a height of 10 meters. At what velocity does the book hit the ground?

user100 [1]

G = 9.81 m/sec^2) g = 9.81 $\frac{meters}{ second^{2} }$

Solving for velocity : 

$velocity^{2}$ = 2gh 
v = $2gh^{ \frac{1}{2} }$
v = (2 x 9.81 x 10)^1/2 
v = 196.2 m/sec (answer)

8 0

4 years ago

Q11) If you were standing at the top of a building and you dropped a rock.

Dafna1 [17]

Answer:

Part A

The distance travel by the rock is approximately 132.496 m

Part B

The speed when the rock hits the ground is approximately 50.96 m/s

Explanation:

Part A

The question is focused on the kinetics equation of a free falling object

The given parameter is the time it takes the rock to hit the ground, t = 5.2 s

For an object in free fall, we have;

h = 1/2·g·t²

Where;

h = The height from which the object is dropped

g = The acceleration due to gravity ≈ 9.8 m/s²

t = The time taken to travel the distance, h = 5.2 s

∴ h = 1/2 × 9.8 m/s² × (5.2 s)² ≈ 132.496 m

The distance travel by the rock, h ≈ 132.496 m

Part B

The speed, 'v', when the rock hits the ground, is given by the following kinematic equation,

v = g·t

∴ v = 9.8 m/s² × 5.2 s = 50.96 m/s

The speed when the rock hits the ground, v ≈ 50.96 m/s.

8 0

3 years ago

What are the conditions required for a rigid body to be in translational equilibrium?

kolezko [41]

Answer:

Explanation:

The condition for translation equilibrium is that is that the net force acting on the body must be zero.

The sum all the external forces acting on the body in horizontal as well as vertical direction must be zero.

∑Fₓ=0 and ∑Fy=0

now if the above two condition are satisfied the rigid body is said to be in translational equilibrium.

God bless... hope this help to clear your doubt.

5 0

3 years ago

On a cold day, the speed of sound in air is 330 m/s. A note with a frequency of 1,320 Hz is played on an instrument. What is the

solmaris [256]

As we know that speed of sound is

$v = 330 m/s$

frequency of sound is

$f= 1320 Hz$

now we know that frequency of sound and speed of sound is related to each other by the following formula

$speed = frequency * wavelength$

$v = \lambda * f$

$330 = 1320 * \lambda$

$\lambda = 0.25 m$

so wavelength of sound is 25 cm or 0.25 m

9 0

3 years ago

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