Question

In the return stroke of a typical lightning bolt, a current of 7.01×10^4 A (70.1 kA). exists for 20 μs. How much charge is transferred in this event ?

Answer 1

Answer:

Charge, q = 1.402 C

Explanation:

Given that,

Current from lightning bolt, $I=7.01\times 10^4\ A$

Time, t = $t=20\ \mu s=2\times 10^{-5}\ s$

Let q is the charge transferred in this event. We know that the total charge divided by time is called current. Mathematically, it is given by :

$I=\dfrac{q}{t}$

$q=I\times t$

$q=7.01\times 10^4\times 2\times 10^{-5}$

q = 1.402 C

So, 1.402 coulomb of charge is transferred in this event. Hence, this is the required solution.