Answer:
The displacement and direction of the body after 2 seconds is 10 meters downwards
Explanation:
The given information are;
From the graph, the acceleration, is seen as the horizontal line that starts from the y-coordinate, y = -5 m/s²
Therefore;
The acceleration of the body after it was released from rest = -5 m/s² with an upward direction;
Which gives, the acceleration of the body downwards = Opposite sign to the acceleration of the body upwards = 5 m/s²
The displacement, s, of the body after 2 seconds is given by the following equation of motion;
s = u·t + 1/2·a·t²
Where;
u = The initial velocity of the body = 0 m/s
t = The time duration of the displacement = 2 s
a = The acceleration of the body = 5 m/s², downwards
Therefore, by substituting the values, we have;
s = 0 × 2 + 1/2 × 5 × 2² = 10 meters
s = 10 meters
The displacement of the body after 2 seconds = 10 meters
Given that the direction of the displacement and the direction of the acceleration are the same, we have;
The displacement and direction of the body after 2 seconds = 10 meters downwards.
