Answer:
Step-by-step explanation:
116f) 5 - |p + 6| = -8
|p + 6| = 13
p + 6 = 13 OR p + 6 = -13
p = 7 OR p = -19
In this case, I think you have to plot a point at 7 and -19.
116a) |7x| = 5
7x = 5 OR 7x = -5
x = OR x =
Again, I think you need to plot points at and
.
Answer: The required solution of the given system is
(x, y) = (3, 1) and (4, 0).
Step-by-step explanation: We are given to solve the following system of equations :
From equation (i), we have
Substituting the value of y from equation (iii) in equation (ii), we get
When, x = 3, then from (iii), we get
And, when x = 4, then from (iii), we get
Thus, the required solution of the given system is
(x, y) = (3, 1) and (4, 0).
Given equation : .
Strategy 1: We can cross mutiply both sides remove fraction form.
On cross multiplication, we get
x * 7 = 3 * 42
7x = 126.
Dividing both sides by 7, we get
<h3>x = 18.</h3>Strategy 2: We can find least common denominator(lcd) of both sides and multiplying both sides by that lcd to get rid denominators from both sides.
LCD of 42 and 7 is 42.
Therefore, multiplying both sides by 42, we get
x = 6 * 3
<h3>x = 18.</h3>