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4 years ago

#2. Find the missing side. Round to the nearest tenth.

Mathematics

1 answer:

kogti [31]4 years ago

5 0

<h3>Answer:</h3>

5.3

<h3>Step-by-step explanation:</h3>

The mnemoic SOH CAH TOA reminds you that ...

... Tan = Opposite/Adjacent

... tan(24°) = x/12

Then multiplying by 12 gives ...

... 12·tan(24°) = x = 5.34274 ≈ 5.3

You might be interested in

<img src="https://tex.z-dn.net/?f=%20-%208y%20%5Cgeqslant%2056" id="TexFormula1" title=" - 8y \geqslant 56" alt=" - 8y \geqslant

SCORPION-xisa [38]

Answer:

y ≤-7

Step-by-step explanation:

-8y ≥56

Divide each side by -8. Remember to flip the inequality

-8y/-8 ≤56/-8

y ≤-7

8 0

3 years ago

Factor completely 4h2 + g.

stiv31 [10]

Answer:

8h + g

Step-by-step explanation

When you say "4h2", do you mean 4h multiplied by 2?

If so, then 4h2 = 8h, and 8h+g would be your answer.

Hope this helps :)

8 0

3 years ago

Read 2 more answers

Three forces act on an object. Two of the forces are at an angle of 95◦ to each other and have magnitudes 35 N and 7 N. The thir

Cerrena [4.2K]

We want to find $\vec F_4$ such that the object needs is in equilibrium:

$\vec F_1+\vec F_2+\vec F_3+\vec F_4=\vec0$

We're told that $F_1=35\,\mathrm N$ , $F_2=7\,\mathrm N$ , and $F_3=9\,\mathrm N$ . We also know the angle between $\vec F_1$ and $\vec F_2$ is 95º, which means

$\vec F_1\cdot\vec F_2=F_1F_2\cos95^\circ=245\cos95^\circ$

$\vec F_3$ is perpendicular to both $\vec F_1$ and $\vec F_2$ , so $\vec F_1\cdot\vec F_3=\vec F_2\cdot\vec F_3=0$ .

If we take the dot product of $\vec F_1$ with the sum of all four vectors, we get

$\vec F_1\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\vec F_1\cdot\vec F_1+\vec F_1\cdot\vec F_2+\vec F_1\cdot\vec F_3+\vec F_1\cdot\vec F_4=0$

${F_1}^2+\vec F_1\cdot\vec F_2+0+\vec F_1\cdot\vec F_4=0$

$\implies\vec F_1\cdot\vec F_4=-\left({F_1}^2+\vec F_1\cdot\vec F_2\right)$

We can do the same thing with $\vec F_2$ and $\vec F_3$ :

$\vec F_2\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\implies\vec F_2\cdot\vec F_4=-\left(\vec F_1\cdot\vec F_2+{F_2}^2\right)$

$\vec F_3\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\implies\vec F_3\cdot\vec F_4=-{F_3}^2$

Finally, if we do this with $\vec F_4$ , we get

$\vec F_4\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\implies{F_4}^2=-\left(\vec F_1\cdot\vec F_4+\vec F_2\cdot\vec F_4+\vec F_3\cdot\vec F_4\right)$

$\implies{F_4}^2=-\left(-\left({F_1}^2+\vec F_1\cdot\vec F_2\right)-\left(\vec F_1\cdot\vec F_2+{F_2}^2\right)-{F_3}^2\right)$

$\implies F_4=\sqrt{{F_1}^2+{F_2}^2+{F_3}^2+2(\vec F_1\cdot\vec F_2)}$

$\implies\boxed{F_4\approx36.2\,\mathrm N}$

7 0

3 years ago

Choose the correct answer

vivado [14]

This is actually called a mapping diagram but the answer is C.

Because the right circle represents the x variable and the left circle is the y variable. So you just follow the arrows. -3 is pointing to 4 so that's a pair or (-3,4)

8 0

4 years ago

A cereal box is 9 1 2 inches long, 5 1 2 inches wide, and 12 inches high. What is the volume of the box?

lara31 [8.8K]

Answer

5603328

Step by step explanation:

Hey! Rmemeber length x width x height!

Multiply: 9 1 2 x 5 1 2 x 12

Answer= 5603328

And thats it! If it is wrong you must have put the wrong numbers in, I dont get why their spaces though....

Have a good day!!

6 0

2 years ago