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Sladkaya [172]
3 years ago
10

Can someone help me?

Mathematics
2 answers:
abruzzese [7]3 years ago
7 0

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 4) ← 2 points on the line

m = \frac{4-0}{0+2} = \frac{4}{2} = 2

Note the line crosses the y- axis at (0, 4) ⇒ c = 4

y = 2x + 4 → A

Oduvanchick [21]3 years ago
5 0

Answer:

A. y = 2x + 4

Step-by-step explanation:

We need to find the equation of the line in slop-intercept form. This is written as y = mx + b. Let m represent the slope and b represent the y intercept.

First lets find the slope. We can do this by finding rise/run.

Two points on the graph:

(0, 4) and (3, 10)

We'll set up the formula like this:

(y2 - y1) ÷ (x2 - x1)

(10 - 4) ÷ (3 - 0)

6 ÷ 3

= 2

This means the slope (m) is 2.

Now we'll find the y-intercept. This is the point where the line crosses the y-axis. If we look at the graph, this is at (0, 4).

This means the y-intercept (b) is 4.

Now plug the values into the equation:

y = mx + b

y = 2x + 4

This is the equation, so the answer is A!

You might be interested in
Q3. Stefan has 4 1/2 cups of oats. He uses 3 1/4 cups to make granola bars for
AleksAgata [21]

Answer:

Days can Stefan feed

Coco with the oats he has left is 5 days

Step-by-step explanation:

Total Oats = 4 1/2 cups

He uses 3 1/4 cups to make granola bars for

a camping trip

Remaining oats after making granola bars = Total oats - oats used for granola bars

= 4 1/2 - 3 1/4

.= 9/2 - 13/4

= 18-13/4

= 5/4 cups

Remaining oats after making granola bars is 5/4 cups

Coco needs 1/4 of a cup of oats each day, how many days can Stefan feed

Coco with the oats he has left?

Days can Stefan feed

Coco with the oats he has left = Remaining oats / 1/4 cups

= 5/4 cups ÷ 1/4 cups

= 5/4 × 4/1

= 20/4

= 5 days

Days can Stefan feed

Coco with the oats he has left is 5 days

5 0
3 years ago
Given a mean of 150 and a standard deviation of 25 Define the interval about the mean that contains 95% of the data.
ohaa [14]
By normal curve symmetry 

<span>from normal table </span>
<span>we have z = 1.15 , z = -1.15 </span>

<span>z = (x - mean) / sigma </span>
<span>1.15 = (x - 150) / 25 </span>
<span>x = 178.75 </span>


<span>z = (x - mean) / sigma </span>
<span>-1.15 = (x - 150) / 25 </span>
<span>x = 121.25 </span>

<span>interval is (121.25 , 178.75) </span>

<span>Pr((121.25-150)/25 < x < (178.75-150)/25) </span>
<span>is about 75%</span>
7 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
kherson [118]

Answer:

The answer is

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

5 0
3 years ago
A boat is marked up 20% on the original price. The original price was
pishuonlain [190]

Answer:

Original price was $50 x 0.20 = 10

original price $50 - 10 = $40 the sale price before sales tax

Step-by-step explanation:

hopefully it helps

3 0
2 years ago
0.6×8 and tell me how you got the answer pls<br><img src="https://tex.z-dn.net/?f=0.6%20%5Ctimes%208" id="TexFormula1" title="0.
Tresset [83]

Answer:

4.8 is the answer!

Step-by-step explanation:

0.6 x 8 = 4.8

6 x 8 = 48

multiply 6 by 8, and move the decimal to the left one time, and get 4.8

7 0
3 years ago
Read 2 more answers
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