The direction of an electric field is determined from the behavior of a positive test charge that is set free in the electric field.This charge moves along a distinct vector showing the direction of the electric field Therefore the answer is b. a positive charge will move in the field.
Snapping a leaf shut around an insect, I think.
Answer:
655128 ohm
Explanation:
C = Capacitance of the capacitor = 7.8 x 10⁻⁶ F
V₀ = Voltage of the battery = 9 Volts
V = Potential difference across the battery after time "t" = 4.20 Volts
t = time interval = 3.21 sec
T = Time constant
R = resistance
Potential difference across the battery after time "t" is given as
T = 5.11 sec
Time constant is given as
T = RC
5.11 = (7.8 x 10⁻⁶) R
R = 655128 ohm
Answer:
<h2>3.00m high</h2>
Explanation:
Gravitational potential energy of the diver is expressed mathematically as
P = mgh
m = mass of the diver (in kg)
g = acceleration due to gravity (in m/s²)
h = the height of the diver above the water surface.
Given m = 85.0kg, g = 9,8m/s² and P = 2.50x10³ Joules, wecan determine how high the diver is above the water surface bu substituting the given values into the formula;
h = P/mg
h = 2.50x10³/85*9.8
h = 2500/833
h ≈ 3.00m
The diver is 3.00m above the water surface.
