What’s the stored energy related to positions of atoms within molecules

A 5.00-pf parallel-plate air-filled capacitor with circular plates is to be used in a circuit in which it will be subjected to p

r-ruslan [8.4K]

A 5 <em>pF</em> parallel-plate air-filled capacitor, with a potential difference equal to 100 Volts and an electric field of 10.000 Volts per meter, must have a plate separation of 10 milimeters, and plate's area equal to 0.0056 meters squared.

<h3>Further explanation</h3>

Capacitors are electrical components use to store electrical energy in the form of potential difference. This is done by putting 2 plates of a conductive material very close to each other, but without getting them into contact. The idea is that, when you charge one plate with (for example) positive charges, the other plate will "feel" this and will charge itself with negative charges (due to the attraction between charges of opposite signs).

The trick is that, even though the charges in the two plates attract each other, they can't come into contact since the 2 plates are separated by a certain distance. Now let's suppose there is only air between the capacitor's plates, we know that air is not a conductive material, however if you charge both plates just enough, you'll be able to make air conduct electricity and so charges from one plate will go to the other and equilibrium will be achieved.

This is the same thing that happens when a lightning strikes the ground. Imagine that the Earth is a gigantic capacitor, with the clouds being one plate and the ground being the other plate. When the clouds are charged enough, air is forced to conduct electricity towards the ground (which is the lightning we see), until equilibrium is achieved. This is the reason why, in Physics, we say that everything is a conductive material if you force it just enough.

Back to our problem... We can compute the separation of the capacitor's plates with the following equation:

$V = E\cdot d$

Which says that the Voltage <em>V</em> is equal to the product of the Electric field <em>E</em> and the distance between the plates <em>d</em>. This equation is valid if the electric field across the capacitor is constant (which for small magnitudes of <em>d</em> it is). So solving for the distance we get:

$d= \frac{V}{E} = \frac{100}{10000} \frac{V}{V/m} = 0.01 m = 10 mm$

Where we can see that the separation of plates is 10 millimeters. Now for the area between the plates we can use this other formula:

$C= \frac{\epsilon \cdot A}{d}$

Where $\epsilon$ is the air's permittivity which has a value of around $8.86 \cdot 10^{-12} \frac{F}{m}$ . By solving for the plate's area, we can find:

$A= \frac{C \cdot d}{\epsilon} = 0.0056 m^2 =$

Which corresponds to a plate's radius of 42.4 millimeters.

<h3>Learn more</h3>

What is electricity: brainly.com/question/9194793
Relation between elementary particles and charge: brainly.com/question/12502147
Another capacitor problem: brainly.com/question/3203280

<h3>Keywords</h3>

Capacitor, Electric charge, Electric field, Voltage

4 0

3 years ago

Read 2 more answers

I NEED HELP :) ty.............

Black_prince [1.1K]

Answer:

The answer to your question is given below

Explanation:

From the question given above, we can see that the wave with a higher frequency has a shorter wavelength while that with a lower frequency has a longer wavelength. This is so because the frequency and wavelength of a wave has inverse relationship. This can further be explained by using the following formula:

Velocity = wavelength x frequency

Divide both side by wavelength

Frequency = Velocity /wavelength

Keeping the velocity constant, we have:

Frequency ∝ 1 / wavelength

From the above illustration, we can see clearly that the frequency and wavelength are in inverse relationship. This implies that the higher the frequency, the shorter the wavelength and the shorter the frequency, the higher the wavelength.

7 0

3 years ago

hypnotist covers a distance of 5 kilometre in one hour and Rahul covers the same distance in 2 hour calculate the speed and stat

adell [148]

Answer:

At 5km/hr; Hypnotist travels with a higher speed.

Explanation:

Let hypnotist be H while Raul be R.

Given the following data;

Distance H = 5km

Time H = 1 hour

Distance R = 5km

Time R = 2 hours

To find the their respective speed;

a. For H;

Speed = distance/time

Speed H = 5/1

Speed H = 5km/hr

b. For R;

Speed = distance/time

Speed R = 5/2

Speed R = 2.5 km/hr

Therefore, hypnotist travels with a higher speed.

3 0

3 years ago

A pickup truck is carrying a toolbox, but the rear gate of the truck is missing, so the box will slide out if it is set moving.

Anon25 [30]

Answer:

t=7.33 s

Explanation:

According to Newton's second law:

$\sum F=m*a$

because we don't want the box to slide, the acceleration has to be zero.

$\sum F=-F_{friction}+F_{truck}=0\\F_{truck}=F_{friction}\\F_{friction}=\µ*m*g=0.500*9.81*m\\F_{friction}=4.91*m$

we know that:

$F=m*a\\4.91m=m*a\\a=4.91m/s^2$

Now having the acceleration, we can use the following formula.

$v_f=a*t\\t=\frac{36.0m/s}{4.91m/s^2}\\\\t=7.33s$

7 0

3 years ago

A boat traveling across a river has a resultant velocity of 10 km/h and travels 34 degrees with respect to the shore. A) What is

vodka [1.7K]

Answer:

a) 1.55 m/s

b) 2.3 m/s

Explanation:

We know that the boat travels across the river, if we define the river as the x-axis, then the velocity of the boat is only on the y-axis.

Then we can write the velocity of the boat in still water as:

S = (0, B)

Now, when the boat is on the river, the velocity of the boat will be equal to the velocity of the boat in still water plus the velocity of the river.

The velocity of the river is:

v = (R, 0).

Then the velocity of the boat in that river is:

V' = (0, B) + (R, 0) = (R, B)

Now, we know that the velocity of the boat is 10km/h, and it travels at an angle of 34° with respect to the shore.

We can use the Pythagoreans theorem to write the components of this velocity as:

x-axis component = 10km/h*cos(34°) = 8.29 km/h

y-axis component = 10km/h*sin(34°) = 5.59 km/h

Then the velocity of the boat can be written in components as:

velocity = ( 8.29 km/h, 5.59 km/h)

And we knew that the velocity of the boat was written as (R, B)

Then we must have:

R = 8.29 km/h

B = 5.59 km/h

a) The speed of the boat in m/s:

We know that the speed of the boat is 5.59 km/h.

First, we know that:

1km = 1000m, then:

5.59 km/h = 5.59*(1000m)h = 5,590 m/h

And we know that:

1h = 3600s

Then we can write:

5,590 m/h = 5,590 m/(3600s) = 1.55 m/s

b) The speed of the river in m/s:

We know that the speed of the river is 8.29 km/h

Using the same reasoning as above, we can do the change of units as follows:

8.29 km/h = 8.29 (1000m)/(3600s) = 2.3 m/s

6 0

3 years ago