Answer:
Work done: 0 J
Change in internal energy: +100 J
Explanation:
- The work done by the gas is given by:
![W=p\Delta V](https://tex.z-dn.net/?f=W%3Dp%5CDelta%20V)
where
p is the gas pressure
is the change in volume of the gas
Since the gas is kept in a rigid container, its volume is fixed, so there is no change in volume: therefore,
and the work done is zero as well:
![W=0](https://tex.z-dn.net/?f=W%3D0)
- The change in internal energy of the gas is given by the 1st law of thermodynamics:
![\Delta U=Q-W](https://tex.z-dn.net/?f=%5CDelta%20U%3DQ-W)
where Q is the heat supplied to the gas. Since W=0 and Q=+100 J, then the change in internal energy of the gas is
![\Delta U=+100 J+0=+100 J](https://tex.z-dn.net/?f=%5CDelta%20U%3D%2B100%20J%2B0%3D%2B100%20J)