What are the basic si units for the speed of light?.

Your teacher's car can go from rest to 25 m/s (≈55 mph) in 10 seconds. The car's velocity changes at a uniform rate. Below is a

Mice21 [21]

If the speed of the car changes uniformly, as shown in the graph, this means that the acceleration is constant. As the acceleration is the derivative of the speed

$a = \frac{\delta v}{\delta t}$

Then, this means that the acceleration is the slope of the equation of the line shown in the graph.

Then, we find the acceleration using the following equation:

$a = \frac{v_f- v_i}{t_2-t_1}\\\\a = \frac{25-0}{10}\\\\a = 2.5\ m/s ^ 2$

Then, the acceleration of the car is $2.5\ m/s^2$

5 0

3 years ago

Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speed up to

SIZIF [17.4K]

Answer:

$5 m/s^2$

Explanation:

The acceleration of the train is given by:

$a=\frac{v-u}{t}$

where:

u = 5 m/s is the initial velocity of the train

v = 45 m/s is the final velocity of the train

t = 8 s is the time taken for the train to increase the velocity

Substituting numbers into the formula, we find

$a=\frac{45 m/s-5 m/s}{8 s}=5 m/s^2$

5 0

4 years ago

Read 2 more answers

Can earthquakes with a magnitude between 3.0 and 6.0 produce high intensity levels?

laiz [17]

3.0 typically is only felt by people who are resting or on the up stairs of buildings. 6.0 is more intense. I would say a 6.0 can produce high intensity levels. A 6.0 can damage buildings of good design and structure. Damagable in poorly built or badly designed structures. Some chimneys may be broken.

5 0

3 years ago

Middle School Physics 5+3 pts

Murljashka [212]

A) The ball on the small ball is far smaller than the force on the basketball.

B) The total momentum before and after the collision remains constant.

C) We know momentum is conserved so we do:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.1 x 5 + 0.6 x 0 = 0.1 x -4 + 0.6 x v₂
v₂ = 1.5 m/s

5 0

3 years ago

What is the best definition for work?

olga55 [171]

Work is done when a force is in the same direction as the object moves.

Explanation:

The work done by a force in moving an object is given by the equation

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement of the object

$\theta$ is the angle between the directions of F and d

From the equation, we notice the following:

Work is done by a force when the force is in the same direction as the object moves. In fact, in this case, $\theta=0^{\circ}$ , and so $cos \theta = 1$ , which means that the work done simply becomes $W=Fd$
When the force is perpendicular to the motion of the object, $\theta=90^{\circ}$ and $cos \theta = 0$ , which means that no work done
Technically, work is also done when the force is not parallel to the motion of the object: in this case, the factor $cos \theta$ means that only the component of the force parallel to the direction of motion contributes to do work on the object.

Therefore, the correct answer is

Work is done when a force is in the same direction as the object moves.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

7 0

4 years ago