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ANTONII [103]
2 years ago
13

What are the basic si units for the speed of light?.

Physics
1 answer:
DanielleElmas [232]2 years ago
7 0
C=meters/second or C=m/s
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Calculate the average Power in kilowatts required to pull a car up a ramp in the amount of work is 250 KJ over a period of 45 se
kherson [118]

For this case we have that by definition, the average power is given by:

P = \frac {W} {t}

Where:

W: It is the work done

t: It's time

According to the data we have to:

W = 250 \ KJ = 250,000 \ J\\t = 45 \ s

So:

P = \frac {250,000} {45}\\P = 5555.55 \ watts = 5.56 \ kw

Answer:

5.56 \ kw

5 0
4 years ago
Determine the MA based on the diagram below.
artcher [175]
There are two things that you should remember while dealing with the "Lever Mechanical Advantage" problems:

1) The Effort Arm;
2) The Resistance Arm.

Some books label the Effort Arm as in-lever arm and the Resistance Arm as out-lever arm. (Physics Jargon that you need to remember in order to solve problems)

The Effort Arm is that "part" of the lever where the force can be applied. The Resistance Arm is where some mass is placed. In the diagram, as you can see, the mass is placed on one arm of the lever. Therefore, it is the Resistance Arm.

Now the formula for the "Mechanical Advantage(MA)" is:
MA =  \frac{L_{e} }{ L_{r} }

Where L_{e} is the length of the Effort Arm(the subscript "e" stands for Effort), and L_{r} stands for the length of the Resistance Arm(here "r" stands for Resistance).

Plug in the values:

L_{e} = 15m.
L_{r} = 7m.

Therefore, L_{e} / L_{r} = 15/7 = 2.143 = MA

The correct answer is option C(2.14).

-i

3 0
3 years ago
Read 2 more answers
Acceleration directed toward the center of a circular path that produces uniform circular motion is
tester [92]
<span>Th answer is Centripetal</span>
4 0
4 years ago
Read 2 more answers
A sled of mass m is given a kick on a frozen pond. The kick imparts to the sled an initial speed of 2.00 m/s . The coefficient o
kobusy [5.1K]

2.04 meters distance is traveled by the sled before stopping.

Mass of the sled = m

The initial speed of the sled = 2 m/s

Coefficient of kinetic friction between sled and ice = 0.100

Let the distance the sled moves before it stops be d.

Gravity = 9.8 m/ s²

Let the initial kinetic energy sled be

= K _{i}

K_{i} =  \frac{1}{2} mv ^{2}

The work done by the frictional force is,

Work \: done \:  by \: frictional \: force =W_{f}

W _{f} = μ_{k}mgd

Work done by frictional force= Initial kinetic energy of the sled

W_{f} = K_{i}

μ_{k}mgd= \frac{1}{2} mv ^{2}

So, the distance traveled by the sled before stopping is

d= \frac{1mv ^{2} }{2 \:μ_{k}mg}

d= \frac{1v ^{2} }{2 \:μ_{k}g}

d= \frac{2^{2} }{2  \times \:0.100 \times 9.8}

d= 2.04 \: m

Therefore, the distance traveled by the sled before stopping is 2.04 meters.

To know more about work done, refer to the below link:

brainly.com/question/13662169

#SPJ4

5 0
2 years ago
A 6.00-mH solenoid is connected in series with a 5.0-μF capacitor and an AC source. The solenoid has internal resistance 3.0 Ω w
son4ous [18]

Answer:

5773.50269 Hz

23 A

Explanation:

L = Inductance = 6 mH

C = Capacitance = 5 μF

R = Resistance = 3 Ω

\epsilon = Maximum emf = 69 V

Resonant angular frequency is given by

\omega=\dfrac{1}{\sqrt{LC}}\\\Rightarrow \omega=\dfrac{1}{\sqrt{6\times 10^{-3}\times 5\times 10^{-6}}}\\\Rightarrow \omega=5773.50269\ Hz

The resonant angular frequency is 5773.50269 Hz

Current is given by

I=\dfrac{\epsilon}{R}\\\Rightarrow I=\dfrac{69}{3}\\\Rightarrow I=23\ A

The current amplitude at the resonant angular frequency is 23 A

7 0
3 years ago
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