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padilas [110]
3 years ago
11

Can someone answer this???

Mathematics
1 answer:
katovenus [111]3 years ago
6 0
3 weeks and 35 dollars
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Match each transformations to the shape it maps shape 1 onto ... Drag the tiles to correct boxes to complete the pairs
rosijanka [135]

Answer:

shape V -----> 90° counterclockwise

shape II ------> 90° clockwise

shape III -----> translation

shape IV -----> 180° rotation


7 0
2 years ago
Read 2 more answers
A manufacturing plant earned $80 per man hour of labor when it opened. Each year, the plant earns an additional 5% per man hour.
Mekhanik [1.2K]

Answer:

The amount that plant earns per man hour after (t) years it open is           $80 (1.05)^{\textrm t} .

Step-by-step explanation:

Given as :

The earning of  manufacturing plant when it opened = $ 80 per man hour

The rate of plant earning per man hour  = 5 %

Let The earning of plant after t years = A( t )

So,

The earning of plant after t years = initial earning × (1+ \dfrac{\textrm rate}{100})^{\textrm Time}

Or, A(t) = $ 80 × (1+ \dfrac{\textrm 5}{100})^{\textrm t}

or, A(t) = $ 80 × (1.05)^{\textrm t}

Hence The amount that plant earns per man hour after (t) years it open is   $80 (1.05)^{\textrm t} . Answer

3 0
3 years ago
Read 2 more answers
X-4y= -2 <br> 3x-y=5<br> in y form
Mamont248 [21]
X-4y=-2
-x. -x
4y=-2-x
4y=x-(-2)
/4. /4
Y=4x+2/4



3x-y=5
-3x. -3x
-y=5-3x
-y=-3x+5
/-1. /-1
Y=3x-5
7 0
2 years ago
What is the equation of the linear function represented by the table?Graph:
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Koi going goindnjrhdnejwjdjsj
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3 years ago
Is it true that the planes x + 2y − 2z = 7 and x + 2y − 2z = −5 are two units away from the plane x + 2y − 2z = 1?
zhuklara [117]

Lets Find It Out..

First we'll find the equation of ALL planes parallel to the original one.

As a model consider this lesson:

Equation of a plane parallel to other

The normal vector is:
<span><span>→n</span>=<1,2−2></span>

The equation of the plane parallel to the original one passing through <span>P<span>(<span>x0</span>,<span>y0</span>,<span>z0</span>)</span></span>is:

<span><span>→n</span>⋅< x−<span>x0</span>,y−<span>y0</span>,z−<span>z0</span>>=0</span>
<span><1,2,−2>⋅<x−<span>x0</span>,y−<span>y0</span>,z−<span>z0</span>>=0</span>
<span>x−<span>x0</span>+2y−2<span>y0</span>−2z+2<span>z0</span>=0</span>
<span>x+2y−2z−<span>x0</span>−2<span>y0</span>+2<span>z0</span>=0</span>

Or

<span>x+2y−2z+d=0</span> [1]
where <span>a=1</span>, <span>b=2</span>, <span>c=−2</span> and <span>d=−<span>x0</span>−2<span>y0</span>+2<span>z0</span></span>

Now we'll find planes that obey the previous formula and at a distance of 2 units from a point in the original plane. (We should expect 2 results, one for each half-space delimited by the original plane.)
As a model consider this lesson:

Distance between 2 parallel planes

In the original plane let's choose a point.
For instance, when <span>x=0</span> and <span>y=0</span>:
<span>x+2y−2z=1</span> => <span>0+2⋅0−2z=1</span> => <span>z=−<span>12</span></span>
<span>→<span>P1</span><span>(0,0,−<span>12</span>)</span></span>

In the formula of the distance between a point and a plane (not any plane but a plane parallel to the original one, equation [1] ), keeping <span>D=2</span>, and d as d itself, we get:

<span><span>D=<span><span>|a<span>x1</span>+b<span>y1</span>+c<span>z1</span>+d|</span><span>√<span><span>a2</span>+<span>b2</span>+<span>c2</span></span></span></span></span>
<span>2=<span><span><span>∣∣</span>1⋅0+2⋅0+<span>(−2)</span>⋅<span>(−<span>12</span>)</span>+d<span>∣∣</span></span><span>√<span>1+4+4</span></span></span></span>
<span><span>|d+1|</span>=2⋅3</span> => <span><span>|d+1|</span>=6</span>First solution:
<span>d+1=6</span> => <span>d=5</span>
<span>→x+2y−2z+5=0</span>Second solution:
<span>d+1=−6</span> => <span>d=−7</span>
<span>→x+2y−2z−7=<span>0</span></span></span>
8 0
2 years ago
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