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Vladimir [108]
3 years ago
7

How much did it increase

Mathematics
1 answer:
trapecia [35]3 years ago
5 0

Answer:

3,498.921

Step-by-step explanation:

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I
Stolb23 [73]

Answer:

The deep of the sand will be 3.5 feet

Step-by-step explanation:

step 1

Find out the area of the court plus a 10-foot boundary around the  court for safety

A=(30+10+10)(60+10+10)\\A=(50)(80)\\A=4,000\ ft^2

step 2

Find the deep of the sand

we know that

The volume of the sand is equal to

V=Ah

where

A is the area of the base

h is the height or deep of the sand

substitute the given values

14,000=(4,000)h

Solve for h

h=14,000/4,000=3.5\ ft

6 0
4 years ago
A is true but f(x) is wrong need help
MrRissso [65]

Answer:

f(x)=-18x^2

Step-by-step explanation:

Given:

1+Integral(f(t)/t^6, t=a..x)=6x^-3

Let's get rid of integral by differentiating both sides.

Using fundamental of calculus and power rule(integration):

0+f(x)/x^6=-18x^-4

Additive Identity property applied:

f(x)/x^6=-18x^-4

Multiply both sides by x^6:

f(x)=-18x^-4×x^6

Power rule (exponents) applied"

f(x)=-18x^2

Check:

1+Integral(-18t^2/t^6, t=a..x)=6x^-3

1+Integral(-18t^-4, t=a..x)=6x^-3

1+(-18t^-3/-3, t=a..x)=6x^-3

1+(6t^-3, t=a..x)=6x^-3

That looks great since those powers are the same on both side after integration.

Plug in limits:

1+(6x^-3-6a^-3)=6x^-3

We need 1-6a^-3=0 so that the equation holds true for all x.

Subtract 1 on both sides:

-6a^-3=-1

Divide both sides by-6:

a^-3=1/6

Raise both sides to -1/3 power:

a=(1/6)^(-1/3)

Negative exponent just refers to reciprocal of our base:

a=6^(1/3)

3 0
3 years ago
What is the size of your_____
Dafna1 [17]
Answer: Hot dog

Set by step explanation: I guess i
5 0
3 years ago
Leticia recently rented an office space and now
LekaFEV [45]

Answer:

uhh......sorry, theres no information here.....tell Leticia to pick the third one for me....

Step-by-step explanation:

8 0
3 years ago
Solve: 2 3 x - 4 = -2 A) -3 B) -4 C) -9 D) 3
Art [367]
Your answer to 2/3x-4= -2 would be
x=3, or letter D
6 0
3 years ago
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