The domain of 13/x - 11 is all real numbers except x cannot equal zero
Answer:
53°
Step-by-step explanation:
It is given that the total measurement of the two angles combined would equate to 116°.
It is also given that m∠WXY is 10° more then m∠ZXY.
Set the system of equation:
m∠1 + m∠2 = 116°
m∠1 = m∠2 + 10°
First, plug in "m∠2 + 10" for m∠1 in the first equation:
m∠1 + m∠2 = 116°
(m∠2 + 10) + m∠2 = 116°
Simplify. Combine like terms:
2(m∠2) + 10 = 116
Next, isolate the <em>variable</em>, m∠2. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 10 from both sides of the equation:
2(m∠2) + 10 (-10) = 116 (-10)
2(m∠2) = 116 - 10
2(m∠2) = 106
Next, divide 2 from both sides of the equation:
(2(m∠2))/2 = (106)/2
m∠2 = 106/2 = 53°
53° is your answer.
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Answer:
Width=6.5 cm
Length=12 cm
Step-by-step explanation:
Step 1: Express the lengths and widths
Width=w
Length=l, but 1 cm less than twice the width=(2×w)-1=2 w-1
Step 2: Solve for the length and width
A=L×W
where;
A=area of the photograph
L=length of the photograph
W=width of the photograph
In our case;
A=91 cm²
L=2 w-1
W=w
91=(2 w-1)w
2 w²-w=91
2 w²-w-91=0, is a quadratic equation
solve for w
w={-1±√(-1²-4×2×-91)}/(2×2)
w=(-1±27)/4
w=(27-1)/4=6.5, or (-1-27)/4=-8
Take w=6.5 cm
L=(2×6.5)-1=13-1=12 cm
Width=6.5 cm
Length=12 cm
250/5 = 50.....so each person is stacking 50 chairs...
50/20 = 2.5 minutes....so it takes each person 2.5 minutes to stack 50 chairs.
so ur answer is 2.5 minutes
Answer:
a
b
Step-by-step explanation:
From the question we are told that
The proportion that has outstanding balance is p = 0.20
The sample size is n = 15
Given that the properties of the binomial distribution apply, for a randomly selected number(X) of credit card
Generally the probability of finding 4 customers in a sample of 15 who have "maxed out" their credit cards is mathematically represented as
=> 
Here C stand for combination
=>
Generally the probability that 4 or fewer customers in the sample will have balances at the limit of the credit card is mathematically represented as
![P(X \le 4) = [ ^{15}C_0 * (0.20)^0 * (1 - 0.20)^{15-0}]+[ ^{15}C_1 * (0.20)^1 * (1 - 0.20)^{15-1}]+\cdots+[ ^{15}C_4 * (0.20)^4 * (1 - 0.20)^{15-4}]](https://tex.z-dn.net/?f=P%28X%20%5Cle%204%29%20%3D%20%20%5B%20%5E%7B15%7DC_0%20%2A%20%280.20%29%5E0%20%2A%20%281%20-%200.20%29%5E%7B15-0%7D%5D%2B%5B%20%5E%7B15%7DC_1%20%2A%20%280.20%29%5E1%20%2A%20%281%20-%200.20%29%5E%7B15-1%7D%5D%2B%5Ccdots%2B%5B%20%5E%7B15%7DC_4%20%2A%20%280.20%29%5E4%20%2A%20%281%20-%200.20%29%5E%7B15-4%7D%5D)
=>
