Let the number of third-graders be x.
We have been given that the number of fourth-graders is 47.
Total number of students = 92.
Therefore, x + 47 = 92
x = 92 - 47
x = 45
Hence, there are 45 third-grade students.
To solve we have to write 12x as 2x+10x
<span><span>x2</span>+2x+10x+20</span>
taking x and 10 as a common
x(x+2)+10(x+2)
now (x+2) is common
<span>(x+2)(x+10) answer</span>
Answer:
38
Step-by-step explanation:
Let the score in the first game be m and in the second be n.
we know that the total score is 35
this means that: m+n=35 .....> equation I
she scored in the second games 6 times as many as in the first one
this means that: n=6m .......> equation II
substitute with equation II in I:
m+6m=35
7m=35
m=5
therefore,
she scored 5 in the first game and 30 in the second one
this means that she scored 30-5=25 points in the second game more than in the first one
1. 15
2. 5
3. Flashcards
Pretty sure this is right, good luck!