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Alenkasestr [34]
3 years ago
5

Which structure of the cell controls what goes in and comes out of the cell?

Biology
1 answer:
belka [17]3 years ago
3 0

Cell Membrane = Controls what comes into and out of a cell; found in plant and animal cells
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4. What is the difference between cytology and histology?
BlackZzzverrR [31]

Answer:

C. Cytology is the study of cells, while histology is the study of tissues

Explanation:

Just learned about cytology, and searched up histology, and it is about tissues. Every other answer is wrong.

Hope this helped :)

5 0
2 years ago
Read 2 more answers
A black swan and a white swan breed and produce offspring that are gray in color. What is the most likely explanation for this h
Andrej [43]
Codominance sudhqjeiwbdjwjsbwkdwn
8 0
3 years ago
2. Dominant trait: cleft chin (C) Mother’s gametes: Cc
andre [41]

.2. Offspring Genotypes will be Cc or cc.

     Offspring phenotypes : Cleft chin or no cleft chin.

    % chance child will have cleft chin: 50%

3.  % chance child will have arched feet: 25%

4.  % chance child will have blonde hair:  50%

5.  % chance child will have normal vision: 25%

 

Explanation:

CASE 1 :

 Dominant trait: cleft chin (C)

    Recessive trait: lacks cleft chin (c)

    Father’s gametes: cc

    Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and  c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents=  \frac{1}{2}C + \frac{1}{2} c........(i)

Gametes of cc parents =<u> </u>\frac{1}{2}c + \frac{1}{2}c .........(ii)

Combining (i) and (ii) we get,

\frac{1}{2}  Cc + \frac{1}{2} cc                              

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin  =\frac{0.5}{1} ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous   (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

     A from mother, a from father =Aa

     a from mother, A from Father = Aa

     a from mother, a from father = aa

Gametes of Aa parent =\frac{1}{2} A + \frac{1}{2} a

Gametes of other Aa parent = \frac{1}{2} A + \frac{1}{2} a

                                       <u>..................................................................................</u>

                                              \frac{1}{4} AA + \frac{1}{4} Aa

                                                                           +  \frac{1}{4} Aa +\frac{1}{4} aa

                                   <u>..........................................................................................</u>

                                <u>\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa</u>

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = \frac{0.25}{1} × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive  (bb)

Father’s gametes: Heterozygous  (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in  half  Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous  (Ff)

Father’s gametes: Heterozygous  (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF  then phenotype farsightedness

Genotype Ff then phenotype  farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

 

3 0
3 years ago
Choose any adaptation found in the desert (hot or cold). Describe how it helps the organism survive and/or reproduce in that bio
horrorfan [7]

Answer:

Cactus spines

Explanation:

The cactus spines keep predators away and prevent different organisms from eating it. This helps it to survive in the desert. Another adaptation is very thick, waxy cuticle help to reduce water loss by evaporation.

4 0
3 years ago
Jenny predicts that when water in a cup evaporates, the mass of the water and cup together will get smaller.
Elden [556K]

A.  Use a scale to measure the mass of a cup of water. Leave the cup out for one day and measure the mass again.

Explanation:

Jenny can predict is evaporation occurs by using a weighing scale to measure that mass of a cup of water, then he leaves the cup out for one day and he measures the mass again.

  • If the mass remains the same, then evaporation did not occur.
  • If evaporation occurs, then the mass will be lesser after the second measurement.
  • From this Jenny can infer the mass loss and made good deductions.
  • Evaporation is a phase change in which liquid turns to vapor.

Learn more:

Evaporation brainly.com/question/10972073

#learnwithBrainly

4 0
3 years ago
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