Question

A pea plant homozygous for the trait of smooth seeds is crossed with a pea plant that is homozygous for the trait of wrinkled seeds. The first generation produces seeds that are all smooth. What percent of the second-generation plants will have smooth seeds when the F1 generation is self-fertilized?

Answer 1

Answer:

100%

Explanation:

A pea plant homozygous for the trait of smooth seeds;

let that be = ss

A pea plant that is homozygous for the trait of wrinkled seeds;

let that be  = ww

if ss crosses with ww; the F1 produces seeds that are all smooth

i.e ss × ww = (sw, sw, sw, sw)

From the  question, we are to find the percentage of the second generation that will produce smooth seeds after self fertilization occurs.

i.e  sw, sw, sw, sw  ×   sw, sw, sw, sw

= the result will yield ssww for all F2 progeny

∴ the percentage of plants that will have smooth seeds when the F1 generation is self-fertiized is 100%