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Kamila [148]
3 years ago
7

A sample of hexane (C6H14) has a mass of 0.580 g. The sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a s

pecific heat of 3.21 J/giK. What amount of heat is produced during the combustion of hexane if the temperature of the calorimeter increases by 4.542 K? Use mc017-1.jpg.
8.46 kJ
16.1 kJ
27.7 kJ
47.8 kJ
Chemistry
2 answers:
valina [46]3 years ago
8 0

Answer:

27.7 kJ

Explanation:

just took it on edge

gulaghasi [49]3 years ago
7 0
The answer is 27.7

According to this equation:
q = M C ΔT
When q= the energy that produced when there is a difference in temperature.
M (g) = amount of the material= 1.900 Kg= 1900 g
ΔT= difference in temperature ( in kelvin or C°)= 4.542 K
C= Specific heat capacity=3.21

∴ q = 1900 * 4.542 * 3.21 = 27701.7 J = 27.7 KJ


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3 0
4 years ago
Find the mass in grams of 3.00 x 1023 molecules of F2
LUCKY_DIMON [66]
<h3>Answer:</h3>

18.9 g F₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.00 × 10²³ molecules F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of F₂ (Diatomic) - 38.00 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.00 \cdot 10^{23} \ molecules \ F_2(\frac{1 \ mol \ F_2}{6.022 \cdot 10^{23} \ molecules \ F_2})(\frac{38.00 \ g \ F_2}{1 \ mol F_2})
  2. Multiply:                                                                                                             \displaystyle 18.9306 \ g \ F_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

18.9306 g F₂ ≈ 18.9 g F₂

8 0
3 years ago
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