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Sonbull [250]
4 years ago
7

2 NaClO3 --> 2 NaCl + 3 O2 In order to produce 6 moles of oxygen gas, how many moles of sodium chlorate are required?

Chemistry
1 answer:
KIM [24]4 years ago
3 0
By using the mol ratio, you can set it as 6mol of O2 times 2Nacl/3O2 to get 4 mols of NaCl.
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"cg" is centigram, which is one-hundredth of a gram.

I will first convert from g to cg (multiply by 100), then from mL to L (multiply by 1000).

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determine the final temperature of a gold nugget parentheses Mass equals 376 G parentheses that starts at 398k and loses 4.85 KJ
maw [93]

Answer:

297.23 K

Explanation:

Given that:

the mass of the gold nugget (m) = 376 g

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Using the formula for calculating the Heat energy

Q = mc\Delta T \\  \\  Q = m\times c\times (T_2-T_1)

-4.85 \times 10^3 = 376 \times  0.128 \times (T_2 - 398) \\ \\ -4.85\times 10^3 =  48.128(T_2 - 398) \\ \\ \dfrac{-4.85\times 10^3}{48.128}= (T_2 - 398) \\ \\-100.77 = T_2 -398\\\\T_2 = -398 +100.77\\ \\ \mathbf{ T_2 = 297.23K}

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