Answer:
0.0900 mol/L
Explanation:
<em>A chemist makes 330. mL of nickel(II) chloride working solution by adding distilled water to 220. mL of a 0.135 mol/L stock solution of nickel(II) chloride in water. Calculate the concentration of the chemist's working solution. Round your answer to significant digits.</em>
Step 1: Given data
- Initial concentration (C₁): 0.135 mol/L
- Initial volume (V₁): 220. mL
- Final concentration (C₂): ?
- Final volume (V₂): 330. mL
Step 2: Calculate the concentration of the final solution
We prepare a dilute solution from a concentrated one. We can calculate the concentration of the working solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁/V₂
C₂ = 0.135 mol/L × 220. mL/330. mL = 0.0900 mol/L
Explanation:
Molecular mass of NO2= 14+16×2=46
1 mole NO2 = 46 gm of NO2
9.4 moles of NO2= 46×9.4 gm= 432.4 gm NO2.
Answer:
1. Covalent Bond
2. Isomers
3. Molecular and Empirical Formula
4. The Structural Formula
5. Diatomic Molecules
1. Hydrogen and Tetraoxosulphate. There are 2 atoms of hydrogen and 4 atoms of tetraoxosulphate.
Explanation:
Sorry, I wrote all I know
<span>Conduction of electricity takes place when there are ions in the medium. The pure water has no ions to conduct electricity. When it has dissolved ions it will conduct electricity. In the case of dry soil it is very resistive to electricity. But when wet it has ions in water molecules among the soil particles. Then the soil becomes a conductor of electricity.</span>