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Pie
3 years ago
6

(Geometry) Explain how you can use a straightedge and a compass to construct an angle that is both congruent and adjacent to a g

iven angle.
Mathematics
2 answers:
Gemiola [76]3 years ago
8 0

Answer:

Given an angle ABC with B as your center you should put the compass with center in B and make an arc with a length that is more than the double of the angle. There you have the intersections between the arc and the segments BA and BC lets say the intersections is D and E, you should open the compass from D to E and make an arc starting D which intersects the previous arc-lets say that intersection is F. Now you should draw a segment using the straight hedge which starts in B and passes through F and ends in a new point let's call that one G with a length similar to AB and BC. So now you have the angle ABG with the center as B which is adjacent and congruent to ABC.


zzz [600]3 years ago
6 0
<span>Use the straightedge to draw two parallel lines and then you draw a line that goes through them that is perpendicular. You then use the compass to measure the angles, they should be congruent and adjacent.

</span>Mark an arc through the sides of the angle. Let the arc intersect the rays at A and B. Continue the arc on past B for a distance. 

<span>Set the compass at B, and to the width of AB. </span>

<span>Still with the compass at B, mark an arc to intersect the first arc at C. </span>

<span>Now you have AB = BC. </span>

<span>Since the radius OA=OB=OC, angles AOB and BOC are congruent.</span>
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A) 1.0 mile <br>b) 5.0 mile <br>c) 5.8 mile <br>d) 0.8 mile ​
nordsb [41]

Answer:

d) 0.8 mile

Step-by-step explanation:

Coordinate of object B = (6, 6)

Coordinate of object C = (1, 4)

Coordinate of the archaeologist = (6, 1)

✍️Distance between Object B (6, 6) and the archaeologist (6, 1):

Distance = |6 - 1| = 5 units = 5 miles

✍️Distance between Object C (1, 4) and the archaeologist (6, 1):

Using the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}, we would have:

d = \sqrt{(6 - 1)^2 + (1 - 4)^2}

d = \sqrt{(5)^2 + (-3)^2}

d = \sqrt{25 + 9}

d = \sqrt{34} = 5.8 units = 5.8 miles (nearest tenth)

Comparing how far each object is from the archaeologist, object C is 0.8 mile (5.8 - 5 = 0.8) farther than object B.

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Answer:

your answer would be (B.)

Step-by-step explanation:

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