Given an angle ABC with B as your center you should put the compass with center in B and make an arc with a length that is more than the double of the angle. There you have the intersections between the arc and the segments BA and BC lets say the intersections is D and E, you should open the compass from D to E and make an arc starting D which intersects the previous arc-lets say that intersection is F. Now you should draw a segment using the straight hedge which starts in B and passes through F and ends in a new point let's call that one G with a length similar to AB and BC. So now you have the angle ABG with the center as B which is adjacent and congruent to ABC.
<span>Use the straightedge to draw two parallel lines and then you draw a line that goes through them that is perpendicular. You then use the compass to measure the angles, they should be congruent and adjacent.
</span>Mark an arc through the sides of the angle. Let the arc intersect the rays at A and B. Continue the arc on past B for a distance.
<span>Set the compass at B, and to the width of AB. </span>
<span>Still with the compass at B, mark an arc to intersect the first arc at C. </span>
<span>Now you have AB = BC. </span>
<span>Since the radius OA=OB=OC, angles AOB and BOC are congruent.</span>
Y=1/16x^2 multiplying both sides by 16 we get: 16y=x^2 The general form of a parabola is: (x-h)^2=4p(y-k) thus 4p=16 p=4 The parabola opens upwrd: Focus: (h,k-p) (0,0-4) =(0,-4) Directrix: y=-4
