Find 3 consecutive odd numbers where the product of the smaller two numbers is 22 less than the square of the largest number.
1 answer:
Answer:
1,3,5
Step-by-step explanation:
1) your 3 consecutive odd integers would be x,x+2,x+4
The smaller two integers are:x and x+2
So
(X)(x+2)=(x+4)^2-22
Distribute
X^2+2x=x^2+16+8x-22
X^2 cancels each other out and 16-22=-6
2x=8x-6
Add 6 on both sides
2x+6=8x
Subtract “2x” on both sides
6=6x
1=x
Hope this helps!
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Answer:
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Step-by-step explanation:
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