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alexandr1967 [171]
3 years ago
9

What's the answer to this question?

Mathematics
2 answers:
Vesnalui [34]3 years ago
7 0
16 1/2 cubic ft I hope this will help you! Have a great day
masha68 [24]3 years ago
4 0
<span>The correct answer is 16 1/2 cubic feet </span>as a mixed number.

Hope this helps.
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chubhunter [2.5K]
My exact answer is 2.2
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4 years ago
A researcher is interested in determining if the more than two thirds of students would support making the Tuesday before Thanks
klio [65]

Answer:

a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they are in favor of making the Tuesday before Thanksgiving a holiday, or they are against. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

So, the binomial probability distribution has two parameters, n and p.

In this problem, we have that n = 1000 and p = \frac{700}{1000} = 0.7. So the parameter is

a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.

8 0
4 years ago
Do you like 1----10<br> cuteeeeee
Sphinxa [80]

Answer:

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Step-by-step explanation:

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3 years ago
Which of the following is a solution
nordsb [41]

\small\boxed{\begin{array}{cc} \hline\sf \normalsize {Math \: \: \: Question}\\ \hline\end{array}}

=================================

Which of the following is a solution

to the linear function y = 4/5 x + 7?

A (0,1)

<u>C (-5,11)</u>

B (15,19)

D (-2,1)

=================================

\begin{gathered}\begin{gathered}\tiny\boxed{\begin{array} {} \red{\bowtie}\:\:\:\: \red{\bowtie}\\。◕‿◕。\end{array}}\end{gathered}\end{gathered}:BrainliestBunch

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3 years ago
Question 17 of 25
iogann1982 [59]

Answer:

I believe it’s C but not 100% sure

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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