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vagabundo [1.1K]
3 years ago
13

-9a + 139 = -1a + 59 what is a?

Mathematics
1 answer:
beks73 [17]3 years ago
3 0
<span>-9a + 139 = -1a + 59

-9a + a= 59 - 139

-8a = - 80

a = 10</span>
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Find the value of 70% of ₹300​
anzhelika [568]

Answer:

70% of 300 is 210

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3 years ago
What is the area of the original rectangle?<br> A.8cm sq<br> B.20cm sq<br> C.25cm sq<br> D.40cm sq
Bumek [7]

Answer:

A. 8 cm sq

Step-by-step explanation:

Find the scale factor

new width/original width

8/1.6=5

calculate length of original rectangle

new length/scale factor

25/5=5cm

Find area of original rectangle

A=l×w

A=1.6×5=8cm²

4 0
3 years ago
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Let a represent the number of ounces of perfume A. Let b represent the number of ounces of perfume B. Perfume A costs $11 per ou
Julli [10]

Answer:

The system of equations in standard form is equal to

11a+19b=71

a+b=5

The number of ounces of perfume A is 3\ ounces

The number of ounces of perfume B is 2\ ounces

Step-by-step explanation:

Let

a-----> the number of ounces of perfume A

b----> the number of ounces of perfume B

we know that

11a+19b=71 -----> equation A

a+b=5

a=5-b -----> equation B

substitute equation B in equation A and solve for b

11(5-b)+19b=71

55-11b+19b=71

8b=71-55

8b=16

b=2\ ounces

Find the value of a

a=5-b -----> a=5-2=3\ ounces

8 0
2 years ago
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I need help with only one question on number 4? anyone pls?
Murljashka [212]
I think 2,-2 is right
4 0
2 years ago
Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds a
kirill115 [55]

Answer:

12 feet per second.

Step-by-step explanation:

Please consider the complete question.

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be representedh(t)=-16t^2+20t.

What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?  

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

\text{Average rate of change}=\frac{h(\frac{1}{2})-h(0)}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot(\frac{1}{2})^2+20\cdot \frac{1}{2}-(-16\cdot(0)^2+20\cdot (0))}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot\frac{1}{4}+10-(0)}{\frac{1}{2}}

\text{Average rate of change}=\frac{-4+10}{\frac{1}{2}}

\text{Average rate of change}=\frac{6}{\frac{1}{2}}

\text{Average rate of change}=\frac{2\cdot 6}{1}

\text{Average rate of change}=12

Therefore, Spot's average rate of ascent is 12 feet per second.

3 0
3 years ago
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