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melisa1 [442]
3 years ago
8

On a coordinate plane, a line is drawn from point A to point B. Point A is at (7, negative 2) and point B is at (negative 8, neg

ative 9). What are the x- and y-coordinates of point C, which partitions the directed line segment from A to B into the ratio 5:8? Round to the nearest tenth, if necessary. x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1 y = (StartFraction m Over m + n EndFraction) (y 2 minus y 1) + y 1 (–2.2, –6.3) (–2.4, –6.4) (2.7, –0.7) (1.2, –4.7)
Mathematics
1 answer:
horrorfan [7]3 years ago
8 0

Answer:

(1.2. - 4.7)

Step-by-step explanation:

On a coordinate plane, a line is drawn from point A to point B. Point A is at (7,-2) and point B is at (-8,-9).

Now, it is asked the x- and y-coordinates of point C, which partitions the directed line segment from A to B into the ratio 5:8.

So, the coordinates of point C are

[\frac{5 \times (- 8) + 8 \times 7}{5 + 8}, \frac{5 \times (- 9) + 8 \times (- 2)}{5 + 8}]

= [\frac{16}{13}, \frac{-61}{13}]

= (1.2. - 4.7) (Answer)

{Round to the nearest tenth}

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