Answer: The answer is D.
Step-by-step explanation: Given that the start does not have "- infinity" you only have "0" as a choice, and "0' is include n the answer I will go with the "[" (greater than or = to ".... Now for the fun one. the third month ends with 150... this is NOT LESS THAN 150 it is EQUAL TO 150 so three is NOT part of the answer....Hat is were the ") comes into play.
Answer:
The answer is....
Step-by-step explanation:
How many hours do you spend each week training for a sports league?
The complete question in the attached figure
Part A) find the perimeter
[perimeter of the garden]=[perimeter square 1]+[perimeter a quarter circle]+[perimeter square 2]
[perimeter square 1]=5+5+5-----> 15 ft
[perimeter square 2]=5+5+5-----> 15 ft
[perimeter a quarter circle]=(2*pi*r)/4------> 2*pi*5/4-----> 7.85 ft
[perimeter of the garden]=[15]+[7.85]+[15]-------> 37.85 ft
the answer Part A) isthe perimeter of the garden is 37.85 ftPart B) Find the area of the garden
[Area of the garden]=[Area square 1]+[Area a quarter circle]+[Area square 2]
[Area square 1]=5*5-----> 25 ft²
[Area square 2]=5*5-----> 25 ft²
[Area a quarter circle]=(pi*r²)/4------> pi*5²/4-----> 19.625 ft²
[Area of the garden]=[25]+[19.625]+[25]-------> 69.625 ft²
the answer Part B) isthe Area of the garden is 69.625 ft²
Answer:
9.6 square inches.
Step-by-step explanation:
We are given that ΔBAC is similar to ΔEDF, and that the area of ΔBAC is 15 inches. And we want to determine the area of ΔDEF.
First, find the scale factor <em>k</em> from ΔBAC to ΔDEF:

Solve for the scale factor <em>k: </em>
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Recall that to scale areas, we square the scale factor.
In other words, since the scale factor for sides from ΔBAC to ΔDEF is 4/5, the scale factor for its area will be (4/5)² or 16/25.
Hence, the area of ΔEDF is:

In conclusion, the area of ΔEDF is 9.6 square inches.
Billy can do 4 hours which is 1000 pictures
and Sandy 3 1/15 hours 500 pictures and 1/15 is 50.
Let me know if I'm wrong
Hope this helps