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bekas [8.4K]
3 years ago
7

A=(1/2)bh =? pls help

Mathematics
2 answers:
Len [333]3 years ago
6 0

Answer:

that formula is the area of a triangle

Step-by-step explanation:

I'm not sure what you are asking but I hope it helps.

Naily [24]3 years ago
4 0

Answer:

this is the formula for area of a trapezoid

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.109 is what in fraction form?
dezoksy [38]

Answer: 109/1000

.109 can not be reduced, so we must put it in a fraction with 1,000.

So, the fraction would be 109/1000, because we need a denominator as 1,000.

The answer = 109/1000

6 0
3 years ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
Explain the difference between finding rational zeros and finding all zeros.
r-ruslan [8.4K]

Answer:

see explanation

Step-by-step explanation:

Given the polynomial

p(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+...+a_2x^2+a_1x+a_o

The rational zeros are all the possible factors of a_0 dived by all the possible factors of a_n. Therefore we use the rational rots theorem to find all possible rational zeros.

To find all zeros we use the remainder theorem. Thus, we plug in all the rational zeros to determine which ones evaluate to zero. These are the real zeros. We could also use long division to find the remaining zeros as soon as we got the first zero with the remainder theorem.

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4 years ago
The sum of three times a number, and 5, is equal to two times the number
omeli [17]
3X + 5 = 2X
X + 5 =0
X = -5

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