Question

Please help me fast. :)

Answer 1

Answer:

1/10

Step-by-step explanation:

it would equally be a 1/10 chance for each number because theyre all evanly spaced and have an equal chance of the pointer landing on that number.

Answer 2

So we want to find out the probability of landing on a number less that 4, and then the probability of landing on an odd number.

In probability, and means that you multiply the probabilities. So the question is:

P(landing on a number less than 4)  x  P(landing on an odd number)

Note: P(  ) stands for 'Probability of .... '

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First, lets work out the first probability: ( Chance of landing on a number less than 4)

We do this by dividing how many numbers are less than 3, by the total number of numbers on the spinner.

So, how many numbers are less than 4?

We know that both 1, 2, and 3 are less than 4, so there are 3 numbers less than 4.

How many numbers are on the spinner?   There are 10   ( 1, 2, 3, 4, 5 and so on up to number 10)

Therefore the probability of landing on a number less that 4 is:

P(landing on a number less than 4) = $\frac{3}{10}$

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Now lets work out the second probability   - P(landing on an odd number)

We get this by dividing the number of odd numbers from 1 to 10, by the total number of numbers on the spinner.

We know that there are 5 odd numbers from 1 to 10  ( 1, 3, 5, 7 and 9)

Therefore the probability of landing on an odd number is:

P(landing on an odd number) = $\frac{5}{10}$

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Now we know that:

P(landing on a number less than 4) = $\frac{3}{10}$

and that  P(landing on an odd number) = tex]\frac{5}{10}[/tex]

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Finally, we just multiply the two probabilities

P(landing on a number less than 4)  x  P(landing on an odd number)

=  $\frac{3}{10}$    x    $\frac{5}{10}$

= $\frac{3}{20}$

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Answer:

c ) $\frac{3}{20}$