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sesenic [268]
3 years ago
7

X^3(x-3)-(x-3)=(x-3)(?) help

Mathematics
1 answer:
docker41 [41]3 years ago
6 0

Answer:

(x-3)(x^3-1)

(x - 3) (x - 1) (x^2 + x + 1)

Step-by-step explanation:

x^3(x-3)-(x-3)=(x-3)(?)

Factor out ( x-3) on the left

(x-3)(x^3-1)=(x-3)(?)

This can be factored further since it is the difference of cubes

a^3 - b^3 = (a−b)(a^2+ab+b^2)

x^3 -1 = (x - 1) (x^2 + x + 1)

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