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krok68 [10]
3 years ago
9

Two bottles are connected with a valve. In bottle A, there are 2.4 L of nitrogen gas at 1.8 atm. In bottle B, there are 4.8 L of

nitrogen gas at 1.8 atm.
After opening the valve, what is the pressure of nitrogen gas?
Please answer in atmospheres.
I will give brainliest please answer quickly!
My
Chemistry
1 answer:
ycow [4]3 years ago
4 0

Answer:

1.8 atm

Explanation:

For bottle "A"

P1 = 1.8 atm V1 = 2.4L, P2 = ?, V2 = 2.4 + 4.8 L = 7.2 L,

Thus using P1•V1 = P2•V2, we have;

P2 = (1.8 × 2.4)/7.2 = 0.6 atm

For bottle "B"

P1 = 1.8 atm, V1 = 4.8L, P2 = ?, V2 = 7.2L,

P2 = (1.8 × 4.8)/7.2 = 1.2 atm

We will now add the individual pressures of each bottle;

Total pressure = P(A) + P(B)

Total pressure = 0.6 + 1.2

Total pressure = 1.8 atm.

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BlackZzzverrR [31]

Answer:

b- The heat capacity ratio increases but output temperature don’t change

Explanation:

The heat capacity is the amount of energy required to raise the temperature of a body, by 1 degree. On the other hand, the specific heat capacity is the amount of heat required to raise the temperature of a of unit mass of a material by 1 degree.

Heat capacity is an extensive property meaning its value depends on the amount of material. Specific heat capacity is found by dividing heat capacity by the mass of the sample, thus making it independent of the amount (intensive property). So if the specific heat capacity increases and the mass of the sample remains the same, the heat capacity must increase too. Because of that options c and d that say that heat capacity reamins same are INCORRECT.

On the other hand, in which has to be with options a and b both say that the heat capacity increases which is correct, but about the output temperatures what happens is that if we increase the specific heat capacity of both fluids that are involved in a process of heat exchange in the same value, the value of the output temperatures do not change so only option a is CORRECT.

8 0
3 years ago
"acid is responsible for the odor in rancid butter. a solution of 0.25 m butyric acid has a ph of 2.71. what is the ka for"
Salsk061 [2.6K]

Answer:- The Ka for the acid is 1.53*10^-^5 .

Solution:- In general, monoprotic acid could be represented by HA. The dissociation equation for the ionization of HA is written as:

HA(aq)\rightarrow H^+(aq) + A^-(aq)

Now, we make the ice table for this equation as:

HA(aq)\rightarrow H^+(aq) + A^-(aq)

I 0.25 0 0

C -X +X +X

E (0.25 - X) X X

where, I stands for initial concentration, C stands for change in concentration and E stands for equilibrium concentration.

X is the change in concentration and from ice table it's same as the concentration of hydrogen ion that is calculated from given pH.

Ka = [H^+][A^-]\frac{1}{HA}

Where, Ka is the acid ionization constant. Let's plug in the values.

Ka = \frac{X^2}{0.25-X}

Let's calculate the value of X first using the equation:

pH = -log[H^+][/tex]

on taking antilog ob above equation we get:

[H^+]=10^-^p^H

[H^+]=10^-^2^.^7^1

[H^+] = 0.00195

So, X = 0.001195

Let's plug in this value of X in the equation:-

Ka=\frac{(0.00195)^2}{0.25-0.00195}

Ka=1.53*10^-^5

So, the value of Ka for butyric acid is 1.53*10^-^5 .

8 0
3 years ago
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Learn more about half life of an isotope here:

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5 0
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Keith_Richards [23]

Answer:

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Explanation:

oxidizing agent in the following equation?

Al (s) + 3 Ag+ (aq) = Al+3 (aq) + 3 Ag (s)

Left side

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Right Side

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So it's balanced already good.

Define

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7 0
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beks73 [17]

Answer:

Hello There!!

Explanation:

When a metal reacts with oxygen gas metal oxide forms.Whenever a compound or element reacts with oxygen It turns to oxide.

hope this helps,have a great day!!

~Pinky~

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