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2 years ago

The chemical formula for propane is: CH3CH2CH3 Calculate the molar mass of propane. Round your answer to 2 decimal places.

Chemistry

1 answer:

Olegator [25]2 years ago

4 0

Answer:

44.11 g/mol

Explanation:

In order to calculate the molar mass of any molecule, we need to add the molar mass of each atom that compounds it:

Molar Mass of C₃H₈ = (Molar Mass of C) * 3 + (Molar Mass of H)*8

Molar Mass of C₃H₈ = (12.01) * 3 + (1.01) * 8

Molar Mass of C₃H₈ = 44.11 g/mol

The molar mass of propane is thus 44.11 g/mol.

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Power is the rate at which energy is?

Mrrafil [7]

In physics, power is the rate of doing work. It is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. In the SI system, the unit of power is the joule per second (J/s), known as the watt in honour of James Watt, the eighteenth-century developer of the steam engine.

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3 years ago

According to Newton’s second law of motion, when an object is acted on by an unbalanced force, how will that object respond? It

otez555 [7]

Answer:

C) It will accelerate.

Explanation:

According to Newton’s second law of motion, when an object is acted on by an unbalanced force, it will accelerate.

An unbalanced force will change the speed or direction (or both) of an object. A change in speed and/or direction is acceleration.

A) is wrong. The object will stop moving only if there is a balanced force in the opposite direction.

B) is wrong. The object will decrease speed only if the unbalanced force has a component opposite to the direction of motion.

d) is wrong. The object will increase speed only if the unbalanced force has a component in the direction of motion.

7 0

3 years ago

Predict the products for the following equation.

coldgirl [10]

Answer: AgCl + Fe

Explanation:

A single replacement reaction is one in which a more reactive element displaces a less reactive element from its salt solution. Thus one element should be different from another element.

A general single displacement reaction can be represented as :

$XY+Z\rightarrow XZ+Y$

The blanced chemical reaction will be :

$3Ag+FeCl_3\rightarrow 3AgCl+Fe$

6 0

2 years ago

4. Chemical formula, mg (Cl0₃)2

grin007 [14]

Answer:

0.017mole

0.0033M

Explanation:

Given parameters:

Formula of the compound:

Mg(ClO₃)₂

Mass of the sample = 3.24g

Unknown:

Number of moles of the sample = ?

Molarity = ?

Solution:

The number of moles of any substance is given as:

Number of moles = $\frac{mass}{volume}$

Molar mass of Mg(ClO₃)₂ = 24 + 2[35.5 + 3(16)] = 191g/mol

Number of moles = $\frac{3.24}{191}$ = 0.017mole

Molarity is the number of moles of a solute in a solution:

Molarity = $\frac{number of moles }{volume}$

Volume given = 5.08L

Molarity = $\frac{0.017}{5.08}$ = 0.0033M

5 0

3 years ago

Calculate the standard reaction Gibbs free energy for the following cell reactions: (a) 2 Ce41(aq) 1 3 I2(aq) S 2 Ce31(aq) 1 I32

Law Incorporation [45]

Answer:

For a: The standard Gibbs free energy of the reaction is -347.4 kJ

For b: The standard Gibbs free energy of the reaction is 746.91 kJ

Explanation:

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$ ............(1)

For a:

The given chemical equation follows:

$2Ce^{4+}(aq.)+3I^{-}(aq.)\rightarrow 2Ce^{3+}(aq.)+I_3^-(aq.)$

Oxidation half reaction: $Ce^{4+}(aq.)\rightarrow Ce^{3+}(aq.)+e^-$ ( × 2)

Reduction half reaction: $3I^_(aq.)+2e^-\rightarrow I_3^-(aq.)$

We are given:

$n=2\\E^o_{cell}=+1.08V\\F=96500$

Putting values in equation 1, we get:

$\Delta G^o=-2\times 96500\times (+1.80)=-347,400J=-347.4kJ$

Hence, the standard Gibbs free energy of the reaction is -347.4 kJ

For b:

The given chemical equation follows:

$6Fe^{3+}(aq.)+2Cr^{3+}+7H_2O(l)(aq.)\rightarrow 6Fe^{2+}(aq.)+Cr_2O_7^{2-}(aq.)+14H^+(aq.)$

Oxidation half reaction: $Fe^{3+}(aq.)\rightarrow Fe^{2+}(aq.)+e^-$ ( × 6)

Reduction half reaction: $2Cr^{2+}(aq.)+7H_2O(l)+6e^-\rightarrow Cr_2O_7^{2-}(aq.)+14H^+(aq.)$

We are given:

$n=6\\E^o_{cell}=-1.29V\\F=96500$

Putting values in equation 1, we get:

$\Delta G^o=-6\times 96500\times (-1.29)=746,910J=746.91kJ$

Hence, the standard Gibbs free energy of the reaction is 746.91 kJ

7 0

3 years ago