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makkiz [27]
3 years ago
11

Calculate the bond dissociation energy needed to break all the bonds in a mole of carbon dioxide, co2.

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
7 0
Draw Lewis dot structure for both. Since H is an exception to the octet rule H2O doesnt require any double bonds. The answer in this question is 920 kj/mol CO2 has 2 double bonds answer is 1464 kj/mol.The bond dissociation energy needed to break all the bond in a mole of carbon dioxide co2 is 920 kj/mol.
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What is the oxidation number of nitrogen in the nitrate ion NO31−?
ahrayia [7]

In No3-1 the oxidation number of oxygen is -5 so oxidation number of N would be +5

8 0
3 years ago
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What is the product when magnesium reacts with nitrogen? Mg(s) + N2(g) → Mg2N3(s) Mg3N(s) Mg3N2(s) MgN3(s)
bixtya [17]
Look at the periodic table to find the charge on atoms.
 Magnesium is +2 and Nitrogen is -3. Since there are two nitrogen charge 2*-3 = -6 there needs to be 3 Mg then (3*2+ = 6+) to pair with the two nitrogen.
3 Mg(+2) + 2 N(-3) = Mg3N2

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3 years ago
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A sample of magnesium oxide has a mass of 94.4 g. How many molecules
ella [17]

Answer: 1.414x10^24 molecules in 94.4g MgO

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molecules in 94.4 g MgO = (94.4/40.204)*avogadro number

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7 0
3 years ago
A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple
miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

\frac{V}{T}=const.

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where in this problem we have:

V_1=490 mL is the initial volume of the gas

T_1=-35.0^{\circ} + 273 = 238 K is the initial temperature

T_2=42.0^{\circ}+273=315 K is the final temperature

Solving for V2, we find the final volume of the gas:

V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL

8 0
3 years ago
Identify the element that has 23 protons
barxatty [35]

Answer:

Vanadium

Explanation:

3 0
2 years ago
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