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telo118 [61]
2 years ago
11

A 74.0-gram piece of metal at 94.0 °C is placed in 120.0 g of water in a calorimeter at 26.5 °C. The final temperature in the ca

lorimeter is 32.0 °C. Determine the specific heat of the metal. Show your work by listing various steps, and explain how the law of conservation of energy applies to this situation.
** I know someone already answered this on another post, but I think their answer is incorrect** I did it and think I have the right answer, but I want to double check it. Thanks!
Chemistry
1 answer:
Aloiza [94]2 years ago
8 0

Answer:

Explanation:

Heat lost by metal = mass x specific heat x fall in temperature

= 74 x S x ( 94 - 32 )

= 4588 S

heat gained by water = mass x specific heat x rise in temperature

= 120 x 1 x ( 32 - 26.5 )   ( specific heat of water is 1 cals / gm )

= 660

Heat lost = heat gained

4588S = 660

S = .14 cal /gm .

Specific heat of metal = .14 cal  / gm

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balu736 [363]
Ammonia is formed by a reaction between hydrogen and nitrogen as shown by the equation below.
N2(g) + 3H2(g) = 2NH3(g)
1 mole of ammonia contains 17 g
Therefore 10.78 g of ammonia are equivalent to 10.78/17 = 0.6341 moles
The mole ratio of hydrogen to ammonia is 3 : 2
Therefore, moles of hydrogen used will be  0.6341 × 3/2 = 0.9512 moles
1 mole of hydrogen is equivalent to 2 g
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6 0
3 years ago
A buffer solution contains 0.120M acetic acid and 0.150M sodium acetate.
Dvinal [7]
A. M x L = moles. 
<span>b. CH3COOH + NaOH ==> CH3COONa + H2O </span>
<span>I...6 mmols....0.......7.5 mmoles </span>
<span>C... 0........0.51 mmols..0 </span>
<span>E...6-0.511 ....0.......7.5+0.511 </span>

<span>I stands for initial </span>
<span>C stands for change. </span>
<span>E stands for equilibrium. </span>
<span>Just divide mmoles by 1000 to convert to moles. I work in mmoles because I get tired of writing those zeros. </span>

<span>c. done as in b.</span>
8 0
3 years ago
What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.
AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

pH=pK_{a} + log(\frac{[Base]}{[Acid]})

According to the given conditions, the equation will become as follow

pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

pH=6.86 + log(\frac{0.058}{0.042})

pH=7.00

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Answer:

How does the energy required to remove an electron from an atom change as you move left to right in Period 4 from potassium through iron? ... A greater nuclear charge pulls the electrons closer to the nucleus, decreasing the atomic radius.

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