Answer:
Part a) 
Part b) 
Step-by-step explanation:we know that
The volume of the sink (half sphere) is equal to

Part a) One cup has a diameter of 6 in. and a height of 8 in. How many cups of water must Michael scoop out of the sink with this cup to empty it?
The volume of the cylinder is equal to

we have
----> the radius is half the diameter

substitute the values

To find the number of cups divide the total volume of the sink by the volume of the cylinder

Round to the nearest whole number

Part b) One cup has a diameter of 10 in. and a height of 8 in. How many cups of water must Michael scoop out of the sink with this cup to empty it?
The volume of the cylinder is equal to

we have
----> the radius is half the diameter

substitute the values

To find the number of cups divide the total volume of the sink by the volume of the cylinder

Let's set up an inequality. t will equal the amount of hours.
123.80 [greater than or equal to] 47 + 9.60t
After isolating t, your answer is t less than or equal to 8. So they can rent the meeting room for at most 8 hours.
Answer:
90 games
Step-by-step explanation:
Given: Total number of team (n) = 10
Each team will play twice with each other.
We know that every team will play two game with each other except with itself, therefore each team will play 
⇒ Each team will play = 
∴ Each team will have 18 games with each other in the league.
Now, as there are total 10 teams and each team have 18 games each, however, we have to make sure that no team have more than two games with other team.
Example: 
Both the above game are same and it is a mistake to take two different game.
∴ Total number of games played by all team= 
⇒ Total games = 
∴ Rana have to schedule 90 games in the Volleyball league.
15+25 /2.
40 /2
Mid segment equals 20
Answer:
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