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salantis [7]
3 years ago
5

The area of a garden is (x^2-x-6) square yards. Find the dimensions of the garden is x=5

Mathematics
1 answer:
kicyunya [14]3 years ago
7 0
I hope this helps you

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Solve x
d1i1m1o1n [39]

Step-by-step explanation:

x^{2} - 4x - 7 = 0

First, let's move the 7 to the right-hand side so we can determine what constant we'll need on the left-hand side to complete the square:

x^{2} - 4x = 7

From here, since the coefficient of the x term is -4, we know the square will be (x - 2) (since -2 it's half of -4).

To complete this square, we will need to add (-2)^{2} to both sides of the equation:

x^{2} - 4x + (-2)^2 = 7 + ^{-2}

x^{2} - 4x + 4 = 7 + 4

(x - 2)^{2} = 11

Now we can take the square root of both sides to figure out the solutions to x:

x - 2 = \pm \sqrt{11}

x = 2 \pm \sqrt{11}

7 0
3 years ago
How many solutions does this linear system have?
Talja [164]
The answer would be A: -2.5, 0
4 0
2 years ago
How many constants are in the following expression?<br> 7x + 4y - 5 + 4x Help
ad-work [718]

Answer:

1

Step-by-step explanation:

-5 is a constant because its a number on its own without a variable

3 0
2 years ago
Read 2 more answers
Help me with this... ​
marin [14]

i. 171

ii. 162

iii. 297

Solution,

n(U)= 630

n(I)= 333

n(T)= 168

i. Let n(I intersection T ) be X

333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \:  - x = 630 - 801 \\ or \:  - x =  - 171 \\ x = 171

<h3>ii.n(only I)= n(I) - n(I intersection T)</h3><h3> = 333 - 171</h3><h3> = 162</h3>

<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

Good luck on your assignment...

4 0
3 years ago
Solve the equation below. SHOW ALL WORK!!!<br><br> −3(y + 2) = 21
Maurinko [17]

Answer:

y=-9

Step-by-step explanation:

-3(y+2)=21

1st Open parenthesis

-3y-6=21

+6       +6

-3y=27

/-3    /-3

y=-9

6 0
2 years ago
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