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3 years ago

How many distinct arrangements are possible using the word CHEER

1 answer:

7 0

You are talking about Arrangement.

So answer will be A(5,5) - C(5,2) = 110.

Reason to deduce C(5,2) is that E is a duplicate.

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I'LL GIVE BRAINLIEST:

Anettt [7]

Answer: D

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

(-2, 11) & (5,6) What is the slope of the equation between these two points?

ololo11 [35]

Answer:

$m =\dfrac{-5}{7}$

Step-by-step explanation:

Given :-

Two points (-2,11) and (5,6) .

And we need to find out the slope of the equation between the two points. The slope of the line passing through two points , is given by ,

$\implies Slope (m) =\dfrac{ y_2-y_1}{x_2-x_1}$

Here the two points are (-2,11) and (5,6) .So put on the respective values ,

$\implies Slope (m) =\dfrac{ 11 - 6}{-2-5}\\\\\implies Slope = \dfrac{5}{-7} \\\\\implies Slope = \dfrac{-5}{7}$

Hence the slope of the line is -5/7 .

8 0

3 years ago

I am thinking of a number.... When I take HALF of my number subtract by 6 I get 5. What is my number?

Crank

answer- 1

step by step explanation-

6-1 =5

two Ka half one

8 0

3 years ago

Read 2 more answers

Two terms of a geometric sequence are given. Find the first five terms. Please help asap

Zepler [3.9K]

Answer:

4, 8, 16, 32, 64

Step-by-step explanation:

The nth term of a geometric sequence is

$a_{n}$ = a₁ $(r)^{n-1}$

Given

a₇ = 256 and a₁₀ = 2048 , then

a₁ $r^{6}$ = 256 → (1)

a₁ $r^{9}$ = 2048 → (2)

Divide (2) by (1)

$\frac{a_{1}r^{9} }{a_{1}r^{6} }$ = $\frac{2048}{256}$

r³ = 8 ( take the cube root of both sides )

r = $\sqrt[3]{8}$ = 2

Substitute r = 2 into (1)

a₁ × $2^{6}$ = 256

a₁ × 64 = 256 ( divide both sides by 64 )

a₁ = 4

Then

a₁ = 4

a₂ = 2a₁ = 2 × 4 = 8

a₃ = 2a₂ = 2 × 8 = 16

a₄ = 2a₃ = 2 × 16 = 32

a₅ = 2a₄ = 2 × 32 = 64

7 0

3 years ago

How do I graph y=2x if there is only slope

lord [1]

There is an invisible +0 at the end. this means the y intercept is 0

3 0

3 years ago