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dolphi86 [110]
2 years ago
11

787476464.1234444×123444848847757747474= ?

Mathematics
2 answers:
user100 [1]2 years ago
3 0

Answer:

9.7209913e+28

babymother [125]2 years ago
3 0
You darn out your mind with the
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Please Help Me With This.
Romashka-Z-Leto [24]

Answer:

A is $0.45 B is 2 ounces

Step-by-step explanation:

A when you divide the cost by the ounces or $5.40 by 12 ounces you get $0.45 per ounce.

B $0.45 times 2 equals 90 cents and you cannot go over 1 dollar.

C you should be to do along with D with this information.

5 0
2 years ago
PLEASE HELP MEE I REALLY NEED HELP NOT TRYING TO BE ANNOYING BUT I NEED HELPP!!! Find the vertex of the graph of the quadratic f
vladimir1956 [14]

Answer:

try math wa y

Step-by-step explanation:

it will give u the answer to most questions the answer is c

3 0
3 years ago
Question 4 of 10
Tresset [83]

Answer:

4. 2. 2. 4. 5. 5. 10. 15.

Step-by-step explanation:

x−1 x+1. = ∞. 2. All the vertical asymptotes of the function f(x) = x2 − 1 x3 − 9x are at. Answer: x = 0 and x = ±3. Solution: Write f(x) = g(x) h(x) ... x→a− f(x) or lim x→a+ f(x) is ±∞. For a = 0, lim x→0+ f(x)=+∞. For a = 3, lim x→3+ f(x)=+∞. ... 5. 10. Which of the following gives the graph of f (x)

3 0
3 years ago
FURTHER MATHEMATICS Use determinants to solve the systems of equation:
maw [93]

Answer:

Step-by-step explanation:

\left\{\begin{array}{ccc}2x+1y+2z&=&13\\1x+1y-2z&=&8\\1x+2y+1z&=&11\\\end{array}\right.\\\\\\\Delta=\left| \begin{array}{ccc}2&1&2\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\0&\frac{1}{2}&-3\\0&1&3\end{array}\right| =2*(\frac{3}{2}+3)=9\\\\

\Delta_1=\left| \begin{array}{ccc}13&1&2\\8&1&-2\\11&2&1\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\8&1&-2\\\frac{11}{2}& 1&\frac{1}{2}\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\-5&0&-4\\\frac{-5}{2}& 0&\frac{5}{2}\end{array}\right| \\\\=2*(-1)*(\frac{-25}{2}-\frac{20}{2}) =45\\

\Delta_2=\left| \begin{array}{ccc}2&13&2\\1&8&-2\\1&11&1\end{array}\right| \\\\\\=\left| \begin{array}{ccc}3&21&0\\3&30&0\\1&11&1\end{array}\right| \\\\\\=1*(90-63) =27\\

\Delta_3=\left| \begin{array}{ccc}2&1&13\\1&1&8\\1&2&11\end{array}\right| \\\\\\=\left| \begin{array}{ccc}0&-1&-3\\0&-1&-3\\1&2&11\end{array}\right| \\\\\\=0\\

\left\{\begin{array}{ccc}x=\dfrac{\Delta_1}{\Delta}=\dfrac{45}{9}=5\\\\y=\dfrac{\Delta_2}{\Delta}=\dfrac{27}{9}=3\\\\z=\dfrac{\Delta_3}{\Delta}=\dfrac{0}{9}=0\\\end{array}\right.

8 0
3 years ago
I need help understanding it.​
sleet_krkn [62]

Answer:

search up the lesson name on yt and then u will know

Step-by-step explanation:

8 0
3 years ago
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