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Minchanka [31]
3 years ago
7

When solving a system of equations graphically, when would you need to estimate the solution? Explain

Mathematics
2 answers:
NikAS [45]3 years ago
9 0

Sample response:

Graphs in which both the x- and y-values for the intersection point are not integers need to be estimated because the lines do not intersect on a grid line where it is easy to read what the values are.

plz rate and thanks! Also I would not get mad if you want to make me brainliest! Pleaseeee!!!

SashulF [63]3 years ago
8 0

Answer:

To solve an equation means to find all the values that should satisfy the given statement. To solve an equation graphically, draw the graph for x and y of the given equation and notice where the curves cuts should be  equal.

Step-by-step explanation:

To solve an equation means to find all the values that should satisfy the given statement. To solve an equation graphically, draw the graph for x and y of the given equation and notice where the curves cuts should be  equal.

Solving system of linear equations by using graph:

A system of linear equations contains atleast two equations.For example y=5x+2 and y=x.The solution of both equations can be denoted as a ordered pair.To solve the system of linear equations we have to plot the points in the graph for both equations in coordinate system must be same.The intersection of two straight lines is the solution(point) for the given system.

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Step-by-step explanation:

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2 years ago
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3 years ago
A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is
tatiyna

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form  has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that  n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

Suppose n=20 and m=5 classrooms

then 13*20=260 ,

260/5=52 students in each classroom,

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