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Debora [2.8K]
3 years ago
8

Help lol pleaseeeee I don’t know what to do

Mathematics
2 answers:
Tanya [424]3 years ago
5 0
I think the answer is 4

If my memory serves me right then you have to do Q3-Q1

This is 6-2

The answer would be 4


Hope this is right and it helps :)
Ierofanga [76]3 years ago
5 0

Answer:

Answer is 4

Step-by-step explanation:

Subtract the lower Quartile which is 2 and the upper quartile which is 6

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WHERE DO THE NUMBERS GO? help!!!!!!
Marat540 [252]

Answer:

Other: \frac{3}{4} , 0.25

Whole Numbers: -20, -6

Natural Numbers: 532, 10, 0, \frac{6}{2}

Step-by-step explanation:

Natural numbers have to be positive whole numbers such as 10 and 0

Whole numbers are similar, but you can have negative numbers here. You just can't put fractions in there.

The 3rd section is a little odd, Integers don't use fractions or decimals, same as whole numbers. The fractions and decimal numbers would go outside of that section.

Extra note: \frac{6}{2} might be a tricky one because it is in fraction form but it is also written as 3. This means it is a natural number. The reason numbers such as \frac{3}{4}  and 0.25 are not natural numbers is because they cannot be put as whole numbers.

6 0
3 years ago
Can someone please help me out
ira [324]

BD \: is \: the \: bisector \: of \: \widehat{ABC} \Rightarrow \widehat{ABD}=\widehat{CBD}  \\\Rightarrow \widehat{ABC} = \widehat{ABD} + \widehat{CBD} = 2\widehat{ABD} = 2 \times 39 = 78° \\ \Rightarrow D. \: 78°

4 0
4 years ago
Read 2 more answers
The probability that a car has a certain factory defect is 825. The probability that a car has a certain factory defect and need
ipn [44]

Answer:

90.91% probability that a car needs an oil change given that it has a certain factory defect

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, we have that:

Event A: having a factory defect.

Event B: needing an oil change.

The probability that a car has a certain factory defect is 825.

So P(A) = 0.825

The probability that a car has a certain factory defect and needs an oil change is 750.

So P(A \cap B) = 0.75

What is the probability that a car needs an oil change given that it has a certain factory defect

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.75}{0.825} = 0.9091

90.91% probability that a car needs an oil change given that it has a certain factory defect

5 0
4 years ago
Savanna had 40 4040 iris blooms last year. This year, she had 15 % 15%15, percent more iris blooms.
Sliva [168]

Answer:

Since this is old, im just gonna get these points, don't wan't them to go to waste lm.ao

Step-by-step explanation:

7 0
3 years ago
I need this help me
Sliva [168]
I THINK that the answer is A
7 0
3 years ago
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