Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Answer: Norm Alpina did better with z-score 0.79
Step-by-step explanation:
Z score formula = (raw score - mean) / standard deviation
For Jack Hartig,
score = 4; mean = 2.9; standard deviation = 2.1
Hence, Z score = (4 - 2.9) /2.1
= 1.1/2.1
= 0.52
For Norm Alpina,
score = 8; mean = 6.5; standard deviation = 1.9
Hence, Z score = (8 - 6.5) /1.9
= 1.5/1.9
= 0.79
Relatively, Norm Alpina did better for having Z score 0.79
Answer:
8x+7
Step-by-step explanation:
Answer:
septagon
Step-by-step explanation:
septagon is the only regular polygon that can make a tessellation
hope it helps .
Answer:
this is your answer. thanks!!