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natima [27]
4 years ago
5

Geothermal energy is possible where there is a.windb.oilc.coald.magma

Chemistry
1 answer:
Leviafan [203]4 years ago
8 0

D magma hope this helps

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What is quanta (keep it very simple)
Nostrana [21]
<span>Quanta are described as discrete packets of energy because it requires a certain amount of energy (not just any amount of energy that is continuous) to excite electrons from one state to another. 


</span>
5 0
3 years ago
A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction:
Vlada [557]

<u>Answer:</u> The cell voltage of the given chemical reaction is 2.74 V

<u>Explanation:</u>

For the given chemical reaction:

Sn^{2+}(aq.)+Ba(s)\rightarrow Ba^{2+}(aq.)+Sn(s)

Here, gold is getting reduced because it is gaining electrons and nickel is getting oxidized because it is loosing electrons.

<u>Oxidation half reaction:</u>  Ba(s)\rightarrow Ba^{2+}(aq.)+2e^-;E^o_{Ba^{2+}/Ba}=-2.90V

<u>Reduction half reaction:</u>  Sn^{2+}(aq.)+2e^-\rightarrow Sn(s);E^o_{Sn^{2+}/Sn}=-0.14V

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=-0.14-(-2.90)=2.76V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Sn^{2+}]}{[Ba^{2+}]}

where,

E_{cell} = electrode potential of the cell = ?V

E^o_{cell} = standard electrode potential of the cell = +2.76 V

n = number of electrons exchanged = 2

[Ba^{2+}]=5.15M

[Sn^{2+}]=1.59M

Putting values in above equation, we get:

E_{cell}=2.76-\frac{0.059}{2}\times \log(\frac{1.59}{5.15})\\\\E_{cell}=2.74V

Hence, the cell voltage of the given chemical reaction is 2.74 V

8 0
4 years ago
Gasoline has a density of 0.7197 grams per milliliter. Calculate the mass, in grams, of a sample of gasoline with a volume of 48
barxatty [35]

Answer:

34.9103 or 34.9 g

Explanation:

Remember Density is a broken heart: m/v.

In this scenario (Let x = # of grams in the sample of gasoline),

D = 0.7198 g/mL = x g / 48.5 mL

So,

(0.7198 g/mL) * (48.5 mL) = x g

x g = 34.9103 = 34.9 g (Accounting for Significant Figures)

8 0
2 years ago
Which of these actions isn’t part of your body’s homeostasis? A. Sweating when your hot B. Breathing harder when u excercise C.
JulijaS [17]
C. It is a reaction to emotion but not to maintain stability. 
4 0
4 years ago
32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa)?
kotegsom [21]
Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.

From the periodic table:
molar mass of oxygen = 16 gm
molar mass of hydrogen = 1 gm
Thus, the molar mass of water vapor = 2(1) + 16 = 18 gm

18 gm of water occupies 22.4 liters, therefore:
volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters

5 0
3 years ago
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