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Lubov Fominskaja [6]
3 years ago
5

32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa)?

Chemistry
1 answer:
kotegsom [21]3 years ago
5 0
Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.

From the periodic table:
molar mass of oxygen = 16 gm
molar mass of hydrogen = 1 gm
Thus, the molar mass of water vapor = 2(1) + 16 = 18 gm

18 gm of water occupies 22.4 liters, therefore:
volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters

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Explanation:

<u>Physical properties of ZBr₂</u>

The compound is an ionic substance. Therefore it will have properties of ionic compounds. Some of these properties are:

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<u>Z is a metal</u>

To form ionic compound, a metal will combine with a non-metal. Bromine is a non-metal and it is expected that Z will be a metal. This is because ionic bonds involves transfer of electron from one specie to the other. Metals are usually the donor and non-metals are the receptor. This is how ionic bond forms. The electrostatic attraction resulting from the ions produced the ionic bond.

<u>Formula of the oxide</u>

ZO

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                +2                         -2

It is obvious that Z has 2 valence electrons. It will lose the two valence electrons to attain stability.

Oxygen requires 2 electrons to resemble Neon. This combination will give a compound ZO.

Learn more:

ionic compounds brainly.com/question/6071838

#learnwithBrainly

               

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