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Lubov Fominskaja [6]
3 years ago
5

32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa)?

Chemistry
1 answer:
kotegsom [21]3 years ago
5 0
Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.

From the periodic table:
molar mass of oxygen = 16 gm
molar mass of hydrogen = 1 gm
Thus, the molar mass of water vapor = 2(1) + 16 = 18 gm

18 gm of water occupies 22.4 liters, therefore:
volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters

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In a molecule of calcium sulfide, calcium has two valence electron bonds, and a sulfur atom has six valence electrons. How many
mote1985 [20]

There are none

<h3>Further explanation</h3>

Given

a molecule of calcium sulfide

two valence electron of Calcium(Ca)

six valence electrons of Sulfur(S)

Required

number of lone pairs of electrons

Solution

Lewis structure shows the form of bonds that occur in the valence electrons of an element or compound

Valence electrons are electrons used in a chemical bond

To achieve stability, the element S needs 2 more electrons which are obtained from 2 electrons from the Ca element,

A lone pair electron means refers to an unshared pair of electrons(not bonding to the other atoms)

This condition usually occurs in covalent bonds

As we know, the bond between Ca, which is a group 2 (metal) with Sulfur in group 16, is an ionic bond because it occurs between metal and non-metal ions, so there is no sharing of electrons, but there is a release of electrons from Ca ions to S ions to form an octet. , so all the valence electrons in S are paired

7 0
3 years ago
how many moles of potassium hydroxide are needed to completely react with 1.73 miles of aluminum sulfate according to the follow
Masteriza [31]
<h3><u>Answer; </u></h3>

=10.38  moles KOH  

<h3><u>Explanation</u>;</h3>

The balanced equation.  

6KOH + Al2(SO4)3 --> 3K2SO4 + 2Al(OH)3  

From the equation;

1 mole of aluminum sulfate requires 6 moles of potassium hydroxide.  

Moles of Aluminium sulfate;  1.73 moles

Moles of KOH;

1 mol Al2(SO4)3 : 6 mol KOH = 1.73  mol Al2(SO4)3 : x mol KOH  

Thus; x =  (6 × 1.73)

              <u> =10.38 moles KOH </u>

4 0
3 years ago
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Answer:

Troposphere

Stratosphere

Mesosphere

Thermosphere

Exosphere

Explanation:

These are all listed in ascending order, hope this helps!

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Answer:

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Explanation:

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BigorU [14]

Answer:

See explaination

Explanation:

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Please see attachment for the step by step solution of the given problem.

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