1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lubov Fominskaja [6]
3 years ago
5

32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa)?

Chemistry
1 answer:
kotegsom [21]3 years ago
5 0
Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.

From the periodic table:
molar mass of oxygen = 16 gm
molar mass of hydrogen = 1 gm
Thus, the molar mass of water vapor = 2(1) + 16 = 18 gm

18 gm of water occupies 22.4 liters, therefore:
volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters

You might be interested in
Arrange the following compounds from left to right in order of increasing percentage by mass of hydrogen: a) H2O, b) C12H26, c)
Nuetrik [128]

Answer:

(A) N4H6  (B) H2O  (C) LiH  (D) C12H26

Explanation:

The given compounds have been arranged  from left to right in order of increasing percentage by mass of hydrogen.

The percent by mass of hydrogen can be calculated by mass of hydrogen in that compound divided by total mass of that compound and finally multiplying the result with 100 to obtain the required percentage.

4 0
3 years ago
Why are some alkali metals stored under oil?
Dahasolnce [82]

due to there reactive rate?

6 0
3 years ago
Read 2 more answers
At standard pressure, ammonia melts at 195 K and boils at 240 K. If a sample of ammonia at standard pressure is cooled from 200
Svetradugi [14.3K]

Answer:

I) the heat capacity of ammonia(s)

II) the heat capacity of ammonia(ℓ)

IV) the enthalpy of fusion of ammonia

Explanation:

Initially, ammonia at 200 K is liquid. To calculate the change of enthalpy from 200 K to 195 K (melting point) we need to know the heat capacity of ammonia(ℓ).

At 195, ammonia is in the transition from liquid to solid (solidification). To calculate the change of enthalpy in that process we need to know the enthalpy of solidification of ammonia, which has the same value but opposite sign to the enthalpy of fusion of ammonia.

From 195 K to 0 K, ammonia is solid. To calculate the change of enthalpy in that process we need to know the heat capacity of ammonia(s).

7 0
3 years ago
On average, tectonic plates move approximately 3 cm per year; about as fast as your fingernails grow
V125BC [204]
True the answer is true :) have a nice day
5 0
3 years ago
gas has an initial volume of 2.4 L at a pressure of 1.5 atm and a temperature of 273 K. The pressure of the gas increases to 4.5
QveST [7]
We are given with two set of conditions. To calculate the final volume, we get first the number of moles under the first condition. Using PV=nRT, the number of moles is equal to 0.16 moles. We substitute this together with the other conditions in PV=nRT, the final volume is 0.92 liters.
8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the sea of instability
    12·2 answers
  • Through the complete electrolysis of a sample of pure water, a student collects 14.0 grams of hydrogen gas and 112.0 grams of ox
    12·1 answer
  • Is a metal baking tray a conductor or insulator or a radiator
    12·2 answers
  • What determines the average kinetic energy of the particles in a gas? A. the number of collisions B. the number of particles C.
    6·2 answers
  • In any chemical compound, the elements are always combined in the same proportion by ___. A. charge B. mass C. volume D. density
    8·1 answer
  • What benefits and drawbacks do you see with maintaining and preserving nature through national parks?
    6·1 answer
  • 6. Matter with a definite volume but no definite shape is a<br> A gas<br> B. solid<br> C.liquid
    13·1 answer
  • If density is calculated by mass divided by volume and the mass increases, what would happen to the density of an object?
    9·1 answer
  • Use the following equation to answer the questions below:
    10·1 answer
  • PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE H
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!