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Lubov Fominskaja [6]

3 years ago

5

32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa)?

1 answer:

kotegsom [21]3 years ago

5 0

Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.

From the periodic table:
molar mass of oxygen = 16 gm
molar mass of hydrogen = 1 gm
Thus, the molar mass of water vapor = 2(1) + 16 = 18 gm

18 gm of water occupies 22.4 liters, therefore:
volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters

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<h3>Answer:</h3>

4.56 × 10^-19 Joules

<h3>Explanation:</h3>

We are given;

Wavelength of the wave as 435.8 nm

We are required to calculate the amount of energy released by an electron.

We know that the speed of the wave, c is 2.998 × 10^8 m/s
But, c = f × λ , where f is the frequency and λ is the wavelength
Energy of a wave is given by the formula;

E = hf , where h is the plank's constant, 6.626 × 10^-34 J-s

But, f = c/λ

Therefore;

f = (2.998 × 10^8 m/s) ÷ (4.358 × 10^-7 m)

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Energy = 6.626 × 10^-34 J-s ×6.879 × 10^14 Hz

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= 4.56 × 10^-19 Joules

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Explanation:

The given data is as follows.

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Formula for specific volume of the refrigerant is as follows.

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