What is quanta (keep it very simple)

1 answer:

5 0

Quanta are described as discrete packets of energy because it requires a certain amount of energy (not just any amount of energy that is continuous) to excite electrons from one state to another.

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Someone pls help with this

Anettt [7]

Question 3 is uniformitarianism
Question 4 is sedimentary rock

5 0

3 years ago

A 0.08024 M solution of NaOH was used to titrate a solution of unknown concentration of HCl. A 32.08 mL sample of the HCl soluti

iris [78.8K]

Answer:

0.08024

Explanation:

4 0

3 years ago

Enter an equation to show how h2po3− can act as a base with hs− acting as an acid. Express your answer as a chemical equation. I

vladimir2022 [97]

The acid - base equation between H2PO3^- and HS^- is H2PO3^- + HS^- ⇄S^- + H3PO3.

An acid is a substance that can donate hydrogen ions while a base is a substance that can accept hydrogen ion. This is the acid base definition according to Brownstead - Lowry.

To show the acid - base relationship between H2PO3^- and HS^-, we have the equation;

H2PO3^- + HS^- ⇄S^- + H3PO3

Learn more about acids and bases: brainly.com/question/10282816

4 0

1 year ago

A dad and his son are driving down the street then wreck, the dad died but the son has to go to the hospital because of his seri

grandymaker [24]

The doctor is His mom

7 0

3 years ago

Read 2 more answers

What compound is formed when methyloxirane (1,2-epoxypropane) is reacted with ethylmagnesium bromide followed by treatment with

Pavlova-9 [17]

Answer:

Pentan-2-ol

Explanation:

On this reaction, we have a Grignard reagent (ethylmagnesium bromide), therefore we will have the production of a carbanion (step 1). Then this carbanion can attack the least substituted carbon in the epoxide in this case carbon 1 (step 2). In this step, the epoxide is open and a negative charge is generated in the oxygen. The next step, is the treatment with aqueous acid, when we add acid the hydronium ion ( $H^+$ ) would be produced, so in the reaction mechanism, we can put the hydronium ion. This ion would be attacked by the negative charge produced in the second step to produce the final molecule: "Pentan-2-ol".

See figure 1

I hope it helps!

5 0

3 years ago