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QveST [7]
3 years ago
8

Which evolutionary process involves the slow addition of allelic variation that increases the hereditary diversity of population

s, ultimately leading to evolutionary change?
Biology
1 answer:
klasskru [66]3 years ago
6 0

Answer:

Mutation

Explanation:

Mutation is a change in the nucleotide sequence by addition, deletion, substitution, etc which results in the slow addition of allelic variation that increases the diversity in a population and leads to evolutionary change.

The right mutation in the allele or gene is favored by nature and it is passed in the next generation through reproduction. Mutation helps in the survival of a population in the continuously changing environment by adding new alleles that increase the fitness of the organism. So the correct answer is mutation.

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Normally, plant roots grow downward,but in space, roots grow in every direction.

Explanation:

Plant roots grow downward ,because it’s easy for them to soak up water and nutrients that make their way into the soil.

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The issue of high cholesterol can sometimes run in families. If an individual has two normal alleles, then he is phenotypically
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Which of these describes transport that uses no energy but requires helper proteins?
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human space exploration is expensive and dangerous. explain why NASA should or should not continue doing it
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3 years ago
A large number of disease-free individuals were enrolled in a study
Nuetrik [128]

Answer:

a,Answer: Type I right censoring, censoring time = 60.

b.This is called an Interval censoring,

c.this is called Random censoring because the year in consideration was chosen at random, censoring time = 61.

d.The observations are left truncated respectively at age 30, 40, 50 and 42.

e.L\alpha \frac{S(60)}{S(30)} *\frac{S(52)-S(55)}{S(40)} *\frac{S(61)}{S(42)} *\frac{S(55)}{S(50)}

Explanation:

a) A healthy individual, enrolled in the study at age 30, never developed

breast cancer during the study.

Answer: Type I censoring, censoring time = 60.

(b) A healthy individual, enrolled in the study at age 40, was diagnosed

with breast cancer at the fifth exam after enrollment (i.e., the disease

started sometime between 12 and 15 years after enrollment).

THis is called an Interval censoring,

if the clinical exams is conducted every three years , then 3*4=12, and 3*5=15

add this to 40 years respectively, we have

censoring time = (52, 55]

c) A healthy individual, enrolled in the study at age 50, died from a

cause unrelated to the disease (i.e., not diagnosed with breast cancer

at any time during the study) at age 61.

this is called Random censoring because the year in consideration was chosen at random, censoring time = 61.

(d) An individual, enrolled in the study at age 42, moved away from

the community at age 55 and was never diagnosed with breast cancer

during the period of observation.

Random censoring, censoring time = 55.

The observations are left truncated respectively at age 30, 40, 50 and 42.

e.  Confining your attention to the four individuals described above,

write down the likelihood for this portion of the study.

L\alpha \frac{S(60)}{S(30)} *\frac{S(52)-S(55)}{S(40)} *\frac{S(61)}{S(42)} *\frac{S(55)}{S(50)}  

the above represent the likelihood

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3 years ago
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