X² - √3x -x +√3
x(x-√3) -(x-√3)
(x-√3)(x-1)
zeroes are x-√3 = 0
x = √3
and x-1 =0
x =1
Answer:
-3/4
Step-by-step explanation:
Option 1
Direction of the line: Down
-Negative Slope
Rise=-3
Run=4
Rise/Run=-3/4
Option 2
Points: (1,-2) and (-3,1)
y2-y1/x2-x1= 1-(-2)/-3-1
1+2/-3-1
-3/4
<h3>
sin22° = 5/4</h3><h3>
tan22° = 3/√55</h3>
As we know that , sinA = opposite/hypotenuse & tanA = opposite/adjacent
So here we can find sin22° , because they already given the sides opposite & hypotenuse . And we can't find tann22° because they given the value of opposite but not given the value of adjacent side of the angle 22°
Now finding the adjacent side using
Pythagoras theorem :-
• Hypotenuse² = Base² + Height²
=> 40² = Base² + 15²
=> 1600 - 225 = Base²
=> Base² = 1375
=> Base = √1375
=> Base = 5√55
Now ,
- tan22° = Opposite/Adjacent = 15/5√55 = 3/√55
- sin22° = Opposite/hypotenuse = 15/40 = 5/4
A quadratic in vertex form can be represented as

a represents reflection over the x-axis, and a vertical stretch or compress
- is reflection and a fraction (1/2) represents a compression.
-h represents a shift of that many units to the right (-2 shifts to the
right two units)
k represents a shift up or down (-2 is shifting down 2 units_
Reflected over the x-axis, Vertically compressed by a factor of 1/2, shifted 2 units to the right, and shifted 2 units down