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pishuonlain [190]
3 years ago
9

a 1385 kg cannon containing a 58.5 kg cannon ball is on wheels. the cannon fires the cannon ball giving it a velocity of 49.8 m/

s north. what is the initial velocity of the cannon the instant after it fires the cannon ball?
Physics
1 answer:
lys-0071 [83]3 years ago
7 0
Conservation of momentum requires that the sum of momenta after is equal to that before.  Since initially nothing is moving, the sum after the shot will also add to zero. 
m₁v₁ = -m₂v₂

Solve for the cannon's velocity v₁

v₁ = -m₂v₂/m₁ = -2.10m/s

The negative sign means it's moving 2.10m/s south.
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B) a polished spoon.
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Three pendulums with strings of the same length and bobs of the same mass are pulled out to angles θ1, θ2, and θ3, respectively,
seropon [69]

Answer:

The angular frequencies of all the 3 pendulums shall be same.

Explanation:

The time period of a simple pendulum with the approximation sin(\theta )\approx \thetais given by:

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The angular frequency \omega is given by

\omega =\frac{2\pi }{T}\\\\\omega =\frac{2\pi}{2\pi \sqrt{\frac{l}{g}}}\\\\\therefore \omega =\sqrt{\frac{g}{l}}

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6 0
4 years ago
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(since you asked for basic understanding only, I am not including actual calculations. Please let me know in the comments section if you wish to verify your solution(s))

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7 0
4 years ago
PLZ PLZ PLZZZZZZZ HELP ASAP!!!
AlladinOne [14]

i belive the answe is c and if im wrong im tarrably sorry

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4 years ago
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LEMME GET SOME HELO HERE PLEASE :))
natita [175]
The answer would be c 
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3 years ago
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